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Exercises · 6.38

Q.Write the conjugate acids for the following Brönsted bases: NH2–, NH3 and HCOO–.

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A Brønsted base's conjugate acid is found by adding one H+^+ to it. Doing this for NH2−\text{NH}_2^-, NH3\text{NH}_3, and HCOO−\text{HCOO}^- gives NH3\text{NH}_3, NH4+\text{NH}_4^+, and HCOOH\text{HCOOH} respectively.

A Brønsted-Lowry base is defined as a proton (H+\text{H}^+) acceptor. Whenever a base accepts a proton, the species it turns into is called its conjugate acid -- the two differ by exactly one H+\text{H}^+ and, correspondingly, one unit of positive charge.

Step 1 -- NH2−\text{NH}_2^- (the amide ion). This ion already carries a negative charge and a lone pair available to accept a proton. Adding H+^+:

NH2−+H+→NH3\text{NH}_2^- + \text{H}^+ \rightarrow \text{NH}_3

So the conjugate acid of NH2−\text{NH}_2^- is NH3\text{NH}_3 (ammonia).

Step 2 -- NH3\text{NH}_3 (ammonia itself). Ammonia's own lone pair can accept a proton too, becoming the ammonium ion:

NH3+H+→NH4+\text{NH}_3 + \text{H}^+ \rightarrow \text{NH}_4^+

So the conjugate acid of NH3\text{NH}_3 is NH4+\text{NH}_4^+.

Step 3 -- HCOO−\text{HCOO}^- (the formate ion). Adding a proton back onto the carboxylate oxygen regenerates the parent acid:

HCOO−+H+→HCOOH\text{HCOO}^- + \text{H}^+ \rightarrow \text{HCOOH} …

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