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Exercises · 6.40

Q.Classify the following species into Lewis acids and Lewis bases and show how these act as Lewis acid/base:

(a) OH –
(b) F–
(c) H+
(d) BCl3 .
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Lewis acids accept an electron pair; Lewis bases donate an electron pair. OH⁻ and F⁻ are Lewis bases (they donate a lone pair), while H⁺ and BCl₃ are Lewis acids (they accept a lone pair).

The key to classifying species as Lewis acids or bases lies in understanding the electron pair — not protons, not charge alone. A Lewis acid is an electron-pair acceptor; a Lewis base is an electron-pair donor. This definition is broader than Brønsted-Lowry, covering species like BCl₃ that have no proton to donate or accept.

Let’s examine each species one by one.


1. OH⁻ (hydroxide ion)

OH⁻ has three lone pairs on oxygen and a negative charge — it is electron-rich. It readily donates a lone pair to form a coordinate bond. For example, when OH⁻ reacts with H⁺:

OH−+H+→H2O\text{OH}^- + \text{H}^+ \rightarrow \text{H}_2\text{O}

Here, OH⁻ donates its lone pair to H⁺. So OH⁻ acts as a Lewis base.

Tip

Every Brønsted-Lowry base (proton acceptor) is also a Lewis base, because accepting a proton requires donating an electron pair to it.


2. F⁻ (fluoride ion)

F⁻ has four lone pairs and a full octet with a negative charge — again, electron-rich. It donates a lone pair to electron-deficient species. For instance, with BF₃:

F−+BF3→[BF4]−\text{F}^- + \text{BF}_3 \rightarrow [\text{BF}_4]^-

F⁻ donates its lone pair to the empty p-orbital on boron. So F⁻ is a Lewis base.


3. H⁺ (proton)

H⁺ has no electrons at all — just a bare nucleus. It desperately needs an electron pair to become stable (as in H₂O or NH₄⁺). When it accepts a lone pair from a base:

H++:NH3→NH4+\text{H}^+ + :\text{NH}_3 \rightarrow \text{NH}_4^+

H⁺ accepts the electron pair. So H⁺ is a Lewis acid. …

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