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Exercises · 6.71

Q.What is the maximum concentration of equimolar solutions of ferrous sulphate and sodium sulphide so that when mixed in equal volumes, there is no precipitation of iron sulphide? (For iron sulphide, K sp = 6.3 × 10⁻¹⁸).

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On mixing equal volumes, each concentration is halved. Setting the ionic product equal to KspK_{sp} gives a maximum concentration of 5.0×10−9 M5.0 \times 10^{-9}\ \text{M} for each solution before FeS\text{FeS} begins to precipitate.

Concept

FeSO4\text{FeSO}_4 supplies Fe2+\text{Fe}^{2+} and Na2S\text{Na}_2\text{S} supplies S2−\text{S}^{2-}. Precipitation of FeS\text{FeS} just begins when the ionic product equals KspK_{sp}:

[Fe2+][S2−]=Ksp=6.3×10−18[\text{Fe}^{2+}][\text{S}^{2-}] = K_{sp} = 6.3 \times 10^{-18}

Solution

Let the concentration of each equimolar solution before mixing be CC. Mixing equal volumes dilutes each species to half:

[Fe2+]=C2,[S2−]=C2[\text{Fe}^{2+}] = \frac{C}{2}, \qquad [\text{S}^{2-}] = \frac{C}{2}

No precipitation as long as the ionic product does not exceed KspK_{sp}: …

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