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Exercises · 6.42

Q.The pH of a sample of vinegar is 3.76. Calculate the concentration of hydrogen ion in it.

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pH is the negative logarithm of hydrogen ion concentration. Working backwards from pH=3.76\text{pH} = 3.76 using [H+]=10−pH[\text{H}^+] = 10^{-\text{pH}} gives a hydrogen ion concentration of 1.74×10−4 M1.74 \times 10^{-4} \, \text{M}.

The pH scale compresses the wide range of hydrogen ion concentrations we encounter in solutions into a manageable set of numbers, typically between 0 and 14. The relationship is logarithmic: each unit change in pH represents a tenfold change in [H+][\text{H}^+]. When we know the pH, we can reverse the definition to extract the actual concentration.

pH=−log⁡10[H+]\text{pH} = -\log_{10}[\text{H}^+]

Rearranging:

[H+]=10−pH[\text{H}^+] = 10^{-\text{pH}}

The second form is what we need here. The antilogarithm (base 10) of the negative pH gives us the molar concentration of hydrogen ions directly.

Step-by-step calculation

  1. Identify the given information.

    The pH of vinegar is 3.763.76.

  2. Apply the inverse relationship.

    Substitute into the formula:

[H+]=10−3.76[\text{H}^+] = 10^{-3.76}

  1. Evaluate the power of ten. We can rewrite this as:

[H+]=10−(3+0.76)=10−3×10−0.76[\text{H}^+] = 10^{-(3 + 0.76)} = 10^{-3} \times 10^{-0.76}

The first part is straightforward: 10−3=0.00110^{-3} = 0.001.

For 10−0.7610^{-0.76}, we use a calculator or antilog table. The value is approximately 0.17380.1738.

  1. Multiply the components.

[H+]=0.001×0.1738=0.0001738 M[\text{H}^+] = 0.001 \times 0.1738 = 0.0001738 \, \text{M}

  1. Express in scientific notation. …

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