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NCERT Exemplar · Q5

Q.Kirchhoff's junction rule is a reflection of

(a) conservation of current density vector.
(b) conservation of charge.
(c) the fact that the momentum with which a charged particle approaches a junction is unchanged (as a vector) as the charged particle leaves the junction.
(d) the fact that there is no accumulation of charges at a junction.
Uttarakhand UbseMCQ· 1mImportance★★★★★
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Kirchhoff's junction rule, ∑Iin=∑Iout\sum I_{in} = \sum I_{out}, is a direct consequence of conservation of charge applied in steady state at a point — and 'charge is conserved at the junction' and 'no charge accumulates at the junction' are the same statement said two ways. Both (b) and (d) are correct; (a) and (c) are not.

Why the rule exists

A junction is just a point where several wires meet. In steady-state current flow, the charge QQ sitting at that point cannot be changing with time — if it were, the junction would be continuously gaining or losing charge forever, which never happens once currents settle down. So

dQdt=0at the junction (steady state).\frac{dQ}{dt} = 0 \quad \text{at the junction (steady state).}

Since current is charge per unit time, dQdt=∑Iin−∑Iout\dfrac{dQ}{dt} = \sum I_{in} - \sum I_{out}. Setting this to zero gives exactly Kirchhoff's junction rule:

∑Iin=∑Iout.\sum I_{in} = \sum I_{out}.

Evaluating each option

  • (a) Wrong. There is no general law that the current density vector J⃗\vec{J} is conserved through a junction — different branches can have different cross-sectional areas and different J⃗\vec J magnitudes/directions; it is the current (the integral of J⃗\vec J over area, i.e. charge/time), not J⃗\vec J itself, that balances.
  • (b) Correct. This is the underlying physical law: electric charge can neither be created nor destroyed, so it cannot pile up at a junction — hence ∑Iin=∑Iout\sum I_{in}=\sum I_{out}. …

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