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Exercise · Q22

Q.Write the IUPAC name of CH3-CH(CH3)-CH2-CH(C2H5)-CH2-CH3, and explain

(i) why the substituents are numbered 2 and 4 rather than 3 and 5, and
(ii) why 'ethyl' is cited before 'methyl' in the final name.
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The molecule is CH3−CH(CH3)−CH2−CH(C2H5)−CH2−CH3\text{CH}_3-\text{CH}(\text{CH}_3)-\text{CH}_2-\text{CH}(\text{C}_2\text{H}_5)-\text{CH}_2-\text{CH}_3, a six-carbon chain (hexane) bearing a methyl branch and an ethyl branch.

(i) Numbering from the left end places the methyl branch on C-2 and the ethyl branch on C-4, giving the locant set {2,4}\{2,4\}. Numbering from the right end instead would place the ethyl branch on C-3 and the methyl branch on C-5, giving the locant set {3,5}\{3,5\}. Comparing {2,4}\{2,4\} with {3,5}\{3,5\} at the first point of difference, 2 is lower than 3, so {2,4}\{2,4\} is the correct, lower locant set, and numbering is fixed from the left end accordingly. …

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