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Example · Example 10

Q.Explain how hyperconjugation operates in propene, CH3-CH=CH2, and identify which C-H bonds are involved.

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In propene, CH3−CH=CH2\text{CH}_3-\text{CH}=\text{CH}_2, the carbon bearing the −CH3-\text{CH}_3 group is attached directly ('alpha') to the carbon-carbon double bond. Each of the three carbon-hydrogen sigma bonds of that methyl group can align, at least partially, with the adjacent pi system of the double bond, allowing electron density from a C-H sigma bond to delocalise into the pi framework.

This delocalisation is drawn as a set of three 'no-bond' resonance structures, one for each of the three alpha C-H bonds: in each such structure, that particular C-H bond is shown as broken, with its electron pair shifted into the pi system, and the hydrogen shown with (formally) no bond to carbon. None of these no-bond structures is a real, separately existing species -- each is only a contributor, alongside the ordinary structure with all bonds intact, to the true, hyperconjugated hybrid. …

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