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Exercise · Q23

Q.Arrange acetic acid (CH3COOH), chloroacetic acid (ClCH2COOH), dichloroacetic acid (Cl2CHCOOH) and trichloroacetic acid (Cl3CCOOH) in increasing order of acid strength, and give the reason for the trend.

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Each of these four acids differs only in how many hydrogen atoms on the α\alpha-carbon have been replaced by chlorine. Chlorine exerts a −I-\text{I} (electron-withdrawing) inductive effect, which stabilises the negatively charged conjugate base (the corresponding carboxylate ion) by withdrawing and spreading out its negative charge; a more stable conjugate base means a stronger acid.

Acetic acid, CH3COOH\text{CH}_3\text{COOH}, has no chlorine at all, so it receives no such −I-\text{I} stabilisation and is the weakest of the four. Chloroacetic acid, ClCH2COOH\text{ClCH}_2\text{COOH}, has one chlorine, giving one unit of −I-\text{I} stabilisation and making it stronger than acetic acid. Dichloroacetic acid, Cl2CHCOOH\text{Cl}_2\text{CHCOOH}, has two chlorines, and their −I-\text{I} effects add together (are cumulative), stabilising the conju …

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