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Exercise · Q25

Q.Explain, in terms of hyperconjugation, why propene (CH3-CH=CH2) is more stable than ethene (CH2=CH2).

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Ethene, CH2=CH2\text{CH}_2=\text{CH}_2, has only hydrogen atoms directly attached to its two double-bond carbons; there is no alkyl group anywhere in the molecule, so there are no carbon-hydrogen sigma bonds positioned on a carbon adjacent to the double bond that could hyperconjugate with it. Ethene therefore receives no hyperconjugative stabilisation at all.

Propene, CH3−CH=CH2\text{CH}_3-\text{CH}=\text{CH}_2, by contrast, has a −CH3-\text{CH}_3 group directly attached to one of its double-bond carbons. Each of the three carbon-hydrogen sigma bonds of that methyl group is positioned alpha to the double bond and can delocalise electron density into the adjacent pi system, exactly as described for Example 10 -- three separate 'no-bond' resonance contributions in total. …

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