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Exercise · Q14

Q.Calculate the energy required to excite an electron in a hydrogen atom from n=1n = 1 to n=2n = 2. Express your answer in both joules and electron volts.

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✓ Free question

The energy of the electron in the nthn^{\text{th}} orbit of hydrogen (Z=1Z=1) is En=−2.18×10−18/n2 JE_n = -2.18 \times 10^{-18}/n^2\ \text{J}.

E1=−2.18×10−18 J,E2=−2.18×10−184=−5.45×10−19 JE_1 = -2.18 \times 10^{-18}\ \text{J}, \qquad E_2 = \frac{-2.18 \times 10^{-18}}{4} = -5.45 \times 10^{-19}\ \text{J}

The energy that must be absorbed to excite the electron from n=1n=1 to n=2n=2 is

ΔE=E2−E1=(−5.45×10−19)−(−2.18×10−18)=1.635×10−18 J\Delta E = E_2 - E_1 = (-5.45 \times 10^{-19}) - (-2.18 \times 10^{-18}) = 1.635 \times 10^{-18}\ \text{J}

Converting to electron volts (1 eV=1.602×10−19 J1\ \text{eV} = 1.602 \times 10^{-19}\ \text{J}):

ΔE=1.635×10−181.602×10−19≈10.2 eV\Delta E = \frac{1.635 \times 10^{-18}}{1.602 \times 10^{-19}} \approx 10.2\ \text{eV}

✓Final answer

The energy required is 1.635×10−18 J1.635 \times 10^{-18}\ \text{J}, which is about 10.2 eV10.2\ \text{eV}.

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