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Question 38 of 40

Q.Prove that the derivative of an odd function is an even function.

West Bengal WbchseWest Bengal HS First Year (WBCHSE Class XI) Annual Examination 2018Subjective· 2mImportance★★★★★
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Differentiate the defining relation of an odd function, f(−x)=−f(x)f(-x)=-f(x), using the chain rule, and compare both sides to show f′f' is even.

Let ff be odd, i.e. f(−x)=−f(x)f(-x)=-f(x) for all xx in its domain.

Differentiate both sides with respect to xx.

Left side (chain rule, differentiating f(−x)f(-x) as a composite function): ddxf(−x)=f′(−x)⋅(−1)=−f′(−x)\dfrac{d}{dx}f(-x)=f'(-x)\cdot(-1)=-f'(-x).

Right side: ddx[−f(x)]=−f′(x)\dfrac{d}{dx}[-f(x)]=-f'(x).

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