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Exercise: Derivatives of Sum/Differen... · Q26

Q.If f(2)=4, f′(2)=3, g(2)=−1, g′(2)=2f(2)=4,\ f'(2)=3,\ g(2)=-1,\ g'(2)=2, find (f+g)′(2)(f+g)'(2) and (f−g)′(2)(f-g)'(2).

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✓ Free question

By the sum and difference rules (Section 9),

(f+g)′(2)=f′(2)+g′(2)=3+2=5,(f−g)′(2)=f′(2)−g′(2)=3−2=1.(f+g)'(2) = f'(2)+g'(2) = 3+2 = 5, \qquad (f-g)'(2) = f'(2)-g'(2) = 3-2 = 1.

(The values f(2)=4, g(2)=−1f(2)=4,\ g(2)=-1 are not needed here -- the sum/difference rule for derivatives uses only f′f' and g′g', not ff and gg themselves.)

✓Final answer

(f+g)′(2)=5,(f−g)′(2)=1(f+g)'(2) = 5,\quad (f-g)'(2) = 1

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