Q.Represent the solution set of $2x - 1 > 5$ (real $x$) on the number line, and state whether the boundary point is included.

[!TLDR] Solve algebraically first, then translate the result to the number line. [!ANSWER] $x > 3$; open circle at $3$, arrow extending right; the point $3$ is NOT included.

Solve $2x-1>5$: add $1$ to both sides, $2x>6$; divide by the positive number $2$, $x>3$. Since the original inequality is strict ($>$), the boundary value $3$ is not included in the solution set. On the number line this is drawn as an open (hollow) circle at $3$, with an arrow extending indefinitely to the right, and nothing marked to the left of $3$. [!ANSWER] $x>3$; open circle at $3$, ray to the right; $3$ excluded.

Solve the inequality algebraically to find the boundary value, then choose an open circle for a strict inequality and draw the arrow in the direction the solution extends.

Using a closed (filled) circle here would incorrectly suggest $x=3$ is a solution, but substituting $x=3$ gives $2(3)-1=5$, which is not strictly greater than $5$.