Skip to content
Numerical · Q16

Q.Two large horizontal plates are held 5.0 mm5.0\ \text{mm} apart, with the space between them completely filled by a liquid of coefficient of viscosity 0.80 Pa⋅s0.80\ \text{Pa·s}. The upper plate is moved horizontally with a steady velocity of 0.20 m/s0.20\ \text{m/s} while the lower plate is kept fixed, setting up streamline flow in the liquid between them. Calculate

(a) the velocity gradient produced in the liquid, and
(b) the tangential (viscous) force required per unit area of the plate to maintain this motion.
West Bengal WbchseTextbookSubjectiveImportance★★★★★
62% · 16/26 Questions
✓ Free question

Given: x=5.0 mm=5.0×10−3 mx = 5.0\ \text{mm} = 5.0\times10^{-3}\ \text{m}, v=0.20 m/sv = 0.20\ \text{m/s}, η=0.80 Pa⋅s\eta = 0.80\ \text{Pa·s}.

  1. Velocity gradient:

    dvdx=vx=0.205.0×10−3=40 s−1\frac{dv}{dx} = \frac{v}{x} = \frac{0.20}{5.0\times10^{-3}} = 40\ \text{s}^{-1}

  2. Shear stress (force per unit area), from Newton's law of viscosity, F/A=η(dv/dx)F/A = \eta (dv/dx):

    FA=(0.80)(40)=32 Pa\frac{F}{A} = (0.80)(40) = 32\ \text{Pa}

    ✓Final answer

    Velocity gradient =40 s−1= 40\ \text{s}^{-1}; tangential force per unit area (shear stress) =32 Pa= 32\ \text{Pa}.

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.