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Example · Example 3

Q.Water (density 1000 kg/m31000\ \text{kg/m}^3, coefficient of viscosity 1.0×10−3 Pa⋅s1.0\times10^{-3}\ \text{Pa·s}) flows through a horizontal pipe of diameter 2.0 cm2.0\ \text{cm} with a steady speed of 0.50 m/s0.50\ \text{m/s}. Calculate the Reynolds number for this flow, and state, giving a reason, whether the flow is likely to be streamline (laminar) or turbulent.

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✓ Free question

Given: ρ=1000 kg/m3\rho = 1000\ \text{kg/m}^3, v=0.50 m/sv = 0.50\ \text{m/s}, d=2.0 cm=0.02 md = 2.0\ \text{cm} = 0.02\ \text{m}, η=1.0×10−3 Pa⋅s\eta = 1.0\times10^{-3}\ \text{Pa·s}.

Re=ρvdη=1000×0.50×0.021.0×10−3=101.0×10−3=1.0×104Re = \frac{\rho v d}{\eta} = \frac{1000\times0.50\times0.02}{1.0\times10^{-3}} = \frac{10}{1.0\times10^{-3}} = 1.0\times10^{4}

Since a Reynolds number below roughly 10001000-20002000 indicates streamline flow and one above roughly 20002000-30003000 indicates turbulent flow, the computed value Re=1.0×104Re = 1.0\times10^4 is far above the turbulence threshold, so the flow through this pipe, at this speed, is turbulent.

✓Final answer

Re=1.0×104Re = 1.0\times10^4; the flow is turbulent, since this is well above the usual threshold value of about 20002000-30003000.

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