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Example · Example 5

Q.A spring of force constant k=200 N/mk = 200\ \text{N/m} is compressed by 0.1 m0.1\ \text{m} from its natural length. Find the elastic potential energy stored in the spring, and the speed with which a block of mass 0.5 kg0.5\ \text{kg} placed against the spring leaves it when released, on a frictionless horizontal surface.

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Given: spring constant k=200 N/mk = 200\ \text{N/m}, compression x=0.1 mx = 0.1\ \text{m}, block mass m=0.5 kgm = 0.5\ \text{kg}, frictionless surface.

Elastic potential energy stored: U=12kx2=12(200)(0.1)2=12(200)(0.01)=1 JU = \frac{1}{2}kx^2 = \frac{1}{2}(200)(0.1)^2 = \frac{1}{2}(200)(0.01) = 1\ \text{J} …

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