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Exercise · Q17

Q.A pendulum bob of mass mm, attached to a string of length LL, is released from rest with the string held horizontal. Using conservation of mechanical energy, find its speed at the lowest point of the swing in terms of LL and gg, and hence find the tension in the string at that lowest point.

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Speed at the lowest point. Released from rest with the string horizontal, the bob falls through a vertical height exactly equal to the string's length LL (from the height of the pivot down to the lowest point of the swing). By conservation of mechanical energy, all of this height's worth of gravitational PE converts into kinetic energy: mgL=12mv2⟹v=2gLmgL = \frac{1}{2}mv^2 \quad\Longrightarrow\quad v = \sqrt{2gL} …

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