Q.State Mendel's Law of Dominance. Illustrate it with reference to a monohybrid cross between a pure-breeding tall ($TT$) and a pure-breeding dwarf ($tt$) garden pea plant, showing the F1 phenotype.

The number of gamete types = 2^(number of heterozygous gene pairs). With three heterozygous pairs (Xx, Yy, Zz), that is 2³ = 8.

By the law of independent assortment, each heterozygous locus contributes 2 possible alleles to a gamete. For $n$ heterozygous gene pairs, the number of genetically different gametes is $2^n$.

Here the genotype XxYyZz is heterozygous at all three loci, so $n = 3$:

$2^n = 2^3 = 8$

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Statement (c) wrongly gives the monohybrid F2 phenotypic ratio as 1:2:1; the true phenotypic ratio is 3:1 (1:2:1 is the genotypic ratio).

Checking each option against Mendelian genetics:

• (a) Dihybrid cross F2 phenotypic ratio = 9:3:3:1 — correct.
• (b) Incomplete dominance F2 phenotypic ratio = 1:2:1 (because heterozygotes show a distinct intermediate phenotype, so genotypic ratio = phenotypic ratio) — correct. …