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Example · Example 1

Q.Write the IUPAC name of (CH3)2CHCH2CH2OH(\text{CH}_3)_2\text{CHCH}_2\text{CH}_2\text{OH} and classify it as a primary, secondary or tertiary alcohol.

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✓ Free question

The longest chain containing the −OH-\text{OH}-bearing carbon is four carbons long, numbered from the OH\text{OH} end to give it the lowest locant, C-1, with a methyl branch at C-3: 3-methylbutan-1-ol. The carbon bearing −OH-\text{OH} (C-1) is bonded to only one other carbon (C-2), so by definition it is a primary alcohol.

✓Final answer

The compound is 3-methylbutan-1-ol, and since its −OH-\text{OH} carbon is attached to only one other carbon, it is a primary alcohol.

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