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Example · Example 18

Q.Explain, using resonance structures, why phenol is more acidic than ethanol, and give the approximate pKa\text{p}K_a values that support this.

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When phenol loses its −OH-\text{OH} proton, the resulting phenoxide ion, C6H5O−\text{C}_6\text{H}_5\text{O}^-, can delocalise its negative charge from oxygen into the aromatic ring: resonance structures place the charge on the ortho and para ring carbons in turn, spreading it over four atoms rather than concentrating it on one oxygen. This delocalisation substantially lowers the phenoxide ion's energy, and a more stable conjugate base means a more favourable, more complete ionisation -- i.e. a stronger acid. When ethanol loses its proton, the resulting ethoxide ion, CH3CH2O−\text{CH}_3\text{CH}_2\text{O}^-, has no adjacent π\pi system to delocalise into (the attached carbon is sp3sp^3), so its negative charge stays fully localised on oxygen -- a comparatively higher-energy, less stabilised ion. This difference is reflected quantitatively in the approximate pKa\text{p}K_a values: phenol, pKa≈10\text{p}K_a \approx 10, versus ethan …

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