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Exercise · Q16

Q.Aniline is converted to benzenediazonium chloride and then boiled with water. Write the reaction sequence and name the final aromatic product.

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Aniline is treated with sodium nitrite and dilute hydrochloric acid at a low temperature (0-5 degrees C, necessary because the resulting diazonium salt decomposes above this range) to give benzenediazonium chloride: C6H5NH2+NaNO2+2HCl→C6H5N2+Cl−+NaCl+2H2O\text{C}_6\text{H}_5\text{NH}_2 + \text{NaNO}_2 + 2\text{HCl} \rightarrow \text{C}_6\text{H}_5\text{N}_2^+\text{Cl}^- + \text{NaCl} + 2\text{H}_2\text{O}. Boiling this diazonium salt with water hydrolyses it: water displaces the diazonium group, releasing nitrogen gas and giving phenol, $\text{C}_6\text{H}_5\text{N}_2^+\text{Cl}^- + \text{H}_2\text{O} \xrig …

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