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Question 39 of 43

Q.(i) Identify the compounds A and B: (CH3)3C-OCH3 --HI--> A + B [1]

(ii) Freshly prepared FeCl3(aq) solution is added to phenol. Mention the reaction with observation and equation. [2] OR
(i) Mention the reagent(s) used for the following conversions: (p) phenol (C6H5-OH) → cyclohexanone-type carbonyl compound (ring with =O) [½] (q) CH3CH2-OH → CH3CH2-OCH3 [½]
(ii) How will you carry out the following conversions: (r) CH3MgI → CH3CH2CH2-OH [1] (s) C6H5-OH → C6H5-OCH3 [1]
West Bengal WbchseWest Bengal HS (WBCHSE) Board 2025Subjective· 3mImportance★★★★★
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Ether cleavage by HI proceeds via the more stable tertiary carbocation; phenol gives a violet colour with FeCl3FeCl_3, a classic phenolic-OH test.

(i) (CH3)3C(CH_3)_3C-OCH3+HIOCH_3 + HI: In acidic ether cleavage, the ether oxygen is first protonated. The C-O bond then breaks heterolytically at whichever carbon can form the more stable carbocation. Here, the tertiary carbon (bearing three methyl groups) can form a stable tertiary carbocation (CH3)3C+(CH_3)_3C^+, so cleavage occurs there (SN1S_N1-type), releasing methanol as the neutral leaving fragment; iodide ion then attacks the carbocation.

(CH3)3C−OCH3+HI→(CH3)3C−I (A)+CH3OH (B)(CH_3)_3C-OCH_3 + HI \rightarrow (CH_3)_3C-I\ (A) + CH_3OH\ (B)

(ii) FeCl3FeCl_3 test on phenol: Freshly prepared neutral aqueous FeCl3FeCl_3 reacts with the phenolic -OH group to form a coloured iron-phenolate complex, giving a characteristic violet/purple colouration — a standard test for the presence of a phenolic (aromatic) -OH group (alcohols do not give this test).

6 C6H5OH+FeCl3→[Fe(OC6H5)6]3−+3H++3HCl (violet complex forms)6\,C_6H_5OH + FeCl_3 \rightarrow [Fe(OC_6H_5)_6]^{3-} + 3H^+ + 3HCl\ \text{(violet complex forms)}

OR (i) Reagents:

(p) Phenol → cyclohexanone: first reduce phenol to cyclohexanol using H2/NiH_2/Ni (catalytic hydrogenation of the aromatic ring), then oxidise/dehydrogenate cyclohexanol to cyclohexanone using CuCu catalyst at 573 K. …

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