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Question 45 of 56

Q.(i) Convert aniline to fluorobenzene. (1 mark)

(ii) Write the structural formulae of the compounds A to D: nitrobenzene --(conc. HNO3 / conc. H2SO4, 100°C)--> A --(NaSH)--> B --(Zn + NH4Cl, 50% Ethanol, Δ)--> C --(Tollen's reagent)--> D. (2 marks) OR An organic compound A (C3H8O) on treatment with Cu dust at 573 K gives B. B does not reduce Fehling's solution but gives a yellow precipitate of compound C with I2/NaOH. Deduce the structures of A, B and C and give their IUPAC names.
West Bengal WbchseWest Bengal HS (WBCHSE) Board 2019Subjective· 3mImportance★★★★★
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Fluorobenzene is made from aniline by diazotisation followed by the Balz-Schiemann reaction; the nitrobenzene sequence demonstrates the step-wise partial reduction of a nitro group (NO2 → NHOH → NO) alongside selective mono-reduction of a dinitro compound.

  1. Aniline to fluorobenzene: C6H5NH2→NaNO2/HCl, 0-5∘CC6H5N2+Cl−→HBF4C6H5N2+BF4−→ΔC6H5F+N2↑+BF3C_6H_5NH_2 \xrightarrow{NaNO_2/HCl,\ 0\text{-}5^\circ C} C_6H_5N_2^+Cl^- \xrightarrow{HBF_4} C_6H_5N_2^+BF_4^- \xrightarrow{\Delta} C_6H_5F + N_2\uparrow + BF_3 This is the Balz-Schiemann reaction: aniline is first diazotised, the diazonium salt is converted to its fluoroborate, and gentle heating (thermal decomposition) releases fluorobenzene, N2 and BF3.
  2. Nitrobenzene sequence:
  • Nitrobenzene →conc. HNO3/conc. H2SO4, 100∘C\xrightarrow{conc.\ HNO_3/conc.\ H_2SO_4,\ 100^\circ C} A = m-dinitrobenzene (the NO2 group is meta-directing, so the second nitro group enters meta to the first).
  • A →NaSH\xrightarrow{NaSH} B = m-nitroaniline: NaSH (or ammonium sulphide) is a classical mild/selective reducing agent that reduces only ONE of the two nitro groups of m-dinitrobenzene to an amino group. …

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