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Question 52 of 66

Q.(i) Write the balanced chemical equation for the reaction of chlorine with hot concentrated sodium hydroxide solution. Is this reaction a disproportionation reaction? Justify.

(ii) Give reason for the following:
(x) Why does nitrogen not form a pentahalide although it shows +5 oxidation state? (y) The structure of the XeF2 molecule is linear, not bent.
(iii) Complete the following reaction: P4 (white) + NaOH (conc.) + H2O -> ? (2+2+1)
West Bengal WbchseWest Bengal HS (WBCHSE) Board 2023Subjective· 5mImportance★★★★★
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Hot concentrated NaOH disproportionates Cl2; nitrogen's lack of d-orbitals blocks a pentahalide; XeF2's lone pairs occupy the equatorial plane, leaving a linear axial F-Xe-F; white phosphorus disproportionates in hot NaOH too.

(i) With hot, concentrated NaOH, chlorine disproportionates further than with cold dilute alkali (which stops at hypochlorite):

3Cl2+6NaOH→hot, conc.5NaCl+NaClO3+3H2O3Cl_2 + 6NaOH \xrightarrow{hot,\ conc.} 5NaCl + NaClO_3 + 3H_2O

This is a disproportionation reaction because the same element, chlorine (oxidation state 0 in Cl2), is simultaneously reduced to Cl- (-1, in NaCl) and oxidised to ClO3- (+5, in NaClO3).

(ii)(x) Nitrogen is in period 2, so its valence shell has only 2s and 2p orbitals available — no d-orbitals. It therefore cannot expand its octet to accommodate 5 bond pairs (10 electrons), so NCl5/NF5-type pentahalides are not possible; phosphorus, with accessible 3d orbitals, can form PCl5.

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