Q.(i) Write the balanced chemical equation for the reaction of chlorine with hot concentrated sodium hydroxide solution. Is this reaction a disproportionation reaction? Justify.
You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.
Start your 14-day free trial to unlock the full solution →Hot concentrated NaOH disproportionates Cl2; nitrogen's lack of d-orbitals blocks a pentahalide; XeF2's lone pairs occupy the equatorial plane, leaving a linear axial F-Xe-F; white phosphorus disproportionates in hot NaOH too.
(i) With hot, concentrated NaOH, chlorine disproportionates further than with cold dilute alkali (which stops at hypochlorite):
This is a disproportionation reaction because the same element, chlorine (oxidation state 0 in Cl2), is simultaneously reduced to Cl- (-1, in NaCl) and oxidised to ClO3- (+5, in NaClO3).
(ii)(x) Nitrogen is in period 2, so its valence shell has only 2s and 2p orbitals available — no d-orbitals. It therefore cannot expand its octet to accommodate 5 bond pairs (10 electrons), so NCl5/NF5-type pentahalides are not possible; phosphorus, with accessible 3d orbitals, can form PCl5.
…
Unlock everything free for 14 days
- Full step-by-step solutions
- Concept-first explanations
- Methods, shortcuts & mistakes
- PYQ mapping + timed mock tests
Full access for 14 days. No credit card required.