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Question 155 of 177

Q.If y=ae5x+be−5xy = a\mathrm{e}^{5x} + b\mathrm{e}^{-5x}, then the differential equation is________.

(a) d2ydx2=25y\dfrac{\mathrm{d}^2y}{\mathrm{d}x^2}=25y
(b) d2ydx2=−25y\dfrac{\mathrm{d}^2y}{\mathrm{d}x^2}=-25y
(c) d2ydx2=−5y\dfrac{\mathrm{d}^2y}{\mathrm{d}x^2}=-5y
(d) d2ydx2=5y\dfrac{\mathrm{d}^2y}{\mathrm{d}x^2}=5y
Maharashtra MsbshseMaharashtra HSC (MSBSHSE) Board 2019MCQ· 1mImportance★★★★★
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Differentiate twice; the exponentials reproduce yy scaled by 2525.

y=ae5x+be−5xy = ae^{5x}+be^{-5x}

dydx=5ae5x−5be−5x\dfrac{dy}{dx} = 5ae^{5x}-5be^{-5x}

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