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Question 153 of 177

Q.Obtain the differential equation by eliminating the arbitrary constants from the following equation: y=c1e2x+c2e−2xy = c_1 e^{2x} + c_2 e^{-2x}.

Maharashtra MsbshseMaharashtra HSC (MSBSHSE) Board 2018Subjective· 2mImportance★★★★★
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Differentiate twice and eliminate c1,c2c_1, c_2 by recognising y′′=4yy''=4y.

Given y=c1e2x+c2e−2xy = c_1e^{2x}+c_2e^{-2x}.

Differentiate once:

dydx=2c1e2x−2c2e−2x\frac{dy}{dx} = 2c_1e^{2x}-2c_2e^{-2x}

Differentiate again:

d2ydx2=4c1e2x+4c2e−2x=4(c1e2x+c2e−2x)=4y\frac{d^2y}{dx^2} = 4c_1e^{2x}+4c_2e^{-2x} = 4\left(c_1e^{2x}+c_2e^{-2x}\right) = 4y

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