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Question 36 of 42

Q.(a) State Bohr's postulate of quantisation of angular momentum of the orbiting electron in hydrogen atom.

(b) Obtain an expression for radius of orbit of electrons in hydrogen atom by using Bohr's postulates. (1+2)
West Bengal WbchseWest Bengal HS (WBCHSE) Board 2023Subjective· 3mImportance★★★★★
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Bohr postulated that angular momentum is quantised in integer multiples of h/2π; combining this with the Coulomb-force-provides-centripetal-force condition gives the orbit radius formula.

  1. Bohr's quantisation postulate: Bohr postulated that an electron can revolve only in certain discrete, stable, non-radiating orbits around the nucleus for which its orbital angular momentum is an integral multiple of h/2πh/2\pi: mvr=nh2π,n=1,2,3,…mvr = \dfrac{nh}{2\pi}, \quad n = 1, 2, 3,\ldots where mm is the electron's mass, vv its speed, rr the orbit radius, hh Planck's constant, and nn the principal quantum number. While in such an orbit, the electron does not radiate energy, despite being accelerated (this was Bohr's ad hoc departure from classical electrodynamics).
  2. Derivation of the orbit radius: For an electron of charge −e-e revolving around a nucleus of charge +e+e (hydrogen atom) in a circular orbit of radius rr, the electrostatic (Coulomb) force provides the centripetal force: 14πε0e2r2=mv2r  ⟹  v2=e24πε0mr...(i)\dfrac{1}{4\pi\varepsilon_0}\dfrac{e^2}{r^2} = \dfrac{mv^2}{r} \implies v^2 = \dfrac{e^2}{4\pi\varepsilon_0 mr} \quad \text{...(i)} From Bohr's quantisation condition: …

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