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Exercise · Q10

Q.Illustrate the law of conservation of charge using the example of β−\beta^- decay, in which a neutron changes into a proton, an electron and an antineutrino, showing that the total charge before and after the decay is unchanged.

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✓ Free question

In β−\beta^- decay, a neutron nn (charge 00) converts into a proton pp, an electron e−e^-, and an antineutrino νˉ\bar\nu:

n⟶p+e−+νˉn \longrightarrow p + e^- + \bar\nu

Charge before the decay: the neutron carries charge qn=0q_n=0.

Charge after the decay: the proton carries qp=+eq_p=+e, the electron carries qe−=−eq_{e^-}=-e, and the antineutrino carries qνˉ=0q_{\bar\nu}=0; their algebraic sum is

qp+qe−+qνˉ=(+e)+(−e)+0=0q_p+q_{e^-}+q_{\bar\nu} = (+e)+(-e)+0 = 0

The total charge is exactly 00 both before and after the decay -- charge is conserved even though the number and identity of the particles present has completely changed, and even in a process (a fundamental particle transformation) that has nothing to do with rubbing or contact.

✓Final answer

Charge before (00) equals charge after (e−e+0=0e-e+0=0): conservation holds exactly.

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