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Numerical · Q26

Q.An infinite plane sheet carries a uniform surface charge density σ=8.85×10−8 C/m2\sigma = 8.85\times10^{-8}\ \text{C/m}^2. Using Gauss's theorem, find the magnitude of the electric field at any point near the sheet (take ϵ0=8.85×10−12 C2N−1m−2\epsilon_0 = 8.85\times10^{-12}\ \text{C}^2\text{N}^{-1}\text{m}^{-2}).

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Concept understanding — Electric Field due to a Uniformly Charged Infinite Plane Sheet

For an infinite, uniformly charged flat sheet (surface density σ\sigma), planar symmetry means E⃗\vec{E} is perpendicular to the sheet on both sides, with equal magnitude at equal perpendicular distances. Choosing a small pillbox Gaussian surface straddling the sheet, with flat end-caps of area AA on each side, the flux is 2EA2EA through the two end-caps (zero through the curved side wall), and the enclosed charge is σA\sigma A; Gauss's theorem gives E=σ/(2ϵ0)E=\sigma/(2\epsilon_0), directed away from the sh …

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