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Numerical · Q23

Q.An electric dipole of moment 5×10−8 C⋅m5\times10^{-8}\ \text{C·m} is placed in a uniform electric field of magnitude 2×104 N/C2\times10^{4}\ \text{N/C} such that the dipole moment makes an angle of 30∘30^\circ with the field. Find the torque on the dipole.

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Given p=5×10−8 C⋅mp=5\times10^{-8}\ \text{C·m}, E=2×104 N/CE=2\times10^4\ \text{N/C}, θ=30∘\theta=30^\circ.

τ=pEsin⁡θ=(5×10−8)(2×104)sin⁡30∘\tau = pE\sin\theta = (5\times10^{-8})(2\times10^4)\sin30^\circ

(5×10−8)(2×104)=1×10−3(5\times10^{-8})(2\times10^4) = 1\times10^{-3}; sin⁡30∘=0.5\sin30^\circ=0.5. …

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