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Exercise · Q7

Q.Write the modified (Ampère-Maxwell) form of Ampère's circuital law, including the displacement current term, and explain in words the physical meaning of each term in it.

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✓ Free question

The law. ∮B⃗⋅dl⃗=μ0(Ic+ϵ0dΦEdt)\oint \vec{B}\cdot d\vec{l} = \mu_0\left(I_c + \epsilon_0\frac{d\Phi_E}{dt}\right)

Meaning of each term. ∮B⃗⋅dl⃗\oint\vec{B}\cdot d\vec{l} is the line integral of the magnetic field around a chosen closed loop -- physically, a measure of how strongly the field 'circulates' around that loop. IcI_c is the ordinary conduction current (actual moving charge) passing through any surface bounded by the loop. ϵ0 dΦE/dt\epsilon_0\,d\Phi_E/dt is Maxwell's displacement current, the rate of change of electric flux ΦE\Phi_E through that same surface, scaled by ϵ0\epsilon_0. μ0\mu_0, the permeability of free space, is the same proportionality constant met in the original (conduction-current-only) form of the law.

Why it is written as a SUM. Both terms genuinely contribute to producing the circulating magnetic field -- a region can have conduction current only (an ordinary wire, away from a capacitor), displacement current only (the gap inside a charging capacitor), or, in general, some of each -- and the corrected law adds their contributions together so the SAME total answer for ∮B⃗⋅dl⃗\oint\vec{B}\cdot d\vec{l} is obtained regardless of which surface, bounded by the same loop, is used to evaluate it (Example 1 and 2 work through the capacitor case in detail).

✓Final answer

∮B⃗⋅dl⃗=μ0(Ic+Id)\oint\vec{B}\cdot d\vec{l}=\mu_0(I_c+I_d) with Id=ϵ0 dΦE/dtI_d=\epsilon_0\,d\Phi_E/dt: the circulating magnetic field around a loop is produced by the TOTAL of the conduction current and the displacement current through any surface the loop bounds.

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