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Numerical · Q23

Q.A magnetic material, when placed in a magnetising field of intensity H=1000 A/mH = 1000\ \text{A/m}, acquires an intensity of magnetisation M=0.5 A/mM = 0.5\ \text{A/m}. Calculate its magnetic susceptibility, its relative permeability, and its absolute permeability, and state whether the material is diamagnetic or paramagnetic.

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Given H=1000 A/mH=1000\ \text{A/m}, M=0.5 A/mM=0.5\ \text{A/m}.

Susceptibility: χ=M/H=0.5/1000=5×10−4\chi = M/H = 0.5/1000 = 5\times10^{-4}.

Relative permeability: μr=1+χ=1+5×10−4=1.0005\mu_r = 1+\chi = 1+5\times10^{-4} = 1.0005.

Absolute permeability: μ=μ0μr=(4π×10−7)×1.0005\mu = \mu_0\mu_r = (4\pi\times10^{-7})\times1.0005

μ≈1.2566×10−6×1.0005≈1.257×10−6 T⋅m/A\mu \approx 1.2566\times10^{-6}\times1.0005 \approx 1.257\times10^{-6}\ \text{T}\cdot\text{m/A} …

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