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Numerical · Q33

Q.A simple magnifying glass of focal length 5 cm5\ \text{cm} is used by a person whose near point is at 25 cm25\ \text{cm}, with the image formed at the near point. Calculate the magnifying power of the lens.

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With the final virtual image formed at the near point, the magnifying power is M=1+Df=1+255=1+5=6M=1+\dfrac{D}{f}=1+\dfrac{25}{5}=1+5=6. The object, viewed through this 5 cm5\ \text{cm}-focal-length lens with the image thrown to the near point, appears 66 times larger (in terms of the …

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