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Question 41 of 60

Q.(a) Deduce the relation μ = sin((A+δm)/2) / sin(A/2), where the symbols have their usual meaning.

(b) A thin prism of 6° angle gives a deviation of 3°. What is the refractive index of the material of the prism? OR A converging lens has a focal length of 24 cm when immersed in water. What is its nature and focal length, if refractive index from air to glass is 1.6 and from air to water is 4/3?
West Bengal WbchseWest Bengal HS (WBCHSE) Board 2022Subjective· 3mImportance★★★★★
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The prism formula follows from geometry of the symmetric ray path at minimum deviation; for a thin prism μ=1+δ/A\mu = 1+\delta/A, giving μ=1.5\mu=1.5 here.

(a) Derivation: For a ray passing through a prism of refracting angle AA, refraction occurs at both faces. Let i1,i2i_1,i_2 be the angles of incidence and emergence, and r1,r2r_1,r_2 the angles of refraction at the two faces. Geometry of the prism gives

A=r1+r2A = r_1+r_2

and the total deviation is

δ=i1+i2−A\delta = i_1+i_2-A

At the angle of minimum deviation δm\delta_m, the ray path becomes symmetric: i1=i2=ii_1=i_2=i and r1=r2=r=A/2r_1=r_2=r=A/2. Then

δm=2i−A  ⇒  i=A+δm2\delta_m = 2i-A \;\Rightarrow\; i = \frac{A+\delta_m}{2}

Applying Snell's law at the first face, μ=sin⁡isin⁡r\mu = \dfrac{\sin i}{\sin r}: …

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