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Example · Example 8

Q.Define the resolving power of a microscope. Derive the expression dmin⁡=1.22λ/(2nsin⁡β)d_{\min}=1.22\lambda/(2n\sin\beta) for the smallest separation between two object points that a microscope can just resolve, and state two ways in which the resolving power of a given microscope can be increased.

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Concept understanding — Resolving Power of a Microscope

For a microscope viewing two point objects separated by distance a, with the objective subtending half-angle α\alpha and immersed in a medium of refractive index n, geometry gives the path difference between extreme rays as 2asin⁡α2a\sin\alpha. For NON-luminous (externally illuminated) objects, Rayleigh's criterion gives amin=λ/(2nsin⁡α)=λ/(2 N.A.)a_{min}=\lambda/(2n\sin\alpha)=\lambda/(2\,\text{N.A.}), where N.A. =nsin⁡α=n\sin\alpha is the numerical aperture. For SELF-luminous point objects, applying Abbe's fuller Airy-disc theory gives instead amin=0.61λ/N.A.a_{min}=0.61\lambda/\text{N.A.}, with resolving power R=1/amin=N.A./(0.61λ)R=1/a_{min}=\text{N.A.}/(0.61\lambda). …

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