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Q.Using Cramer's rule, solve the following system of equations : 2x1+3x2=52x_1 + 3x_2 = 5 11x1−5x2=611x_1 - 5x_2 = 6

CBSECBSE Class XII Board 2024Subjective· 2mImportance★★★★★
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With D=−43, D1=−43, D2=−43D=-43,\ D_1=-43,\ D_2=-43, Cramer's rule gives x1=1, x2=1x_1=1,\ x_2=1.

For a1x1+b1x2=c1, a2x1+b2x2=c2a_1x_1+b_1x_2=c_1,\ a_2x_1+b_2x_2=c_2: x1=D1D, x2=D2Dx_1=\dfrac{D_1}{D},\ x_2=\dfrac{D_2}{D} where D=∣a1b1a2b2∣D=\begin{vmatrix}a_1&b_1\\a_2&b_2\end{vmatrix}, D1D_1 replaces column 1 with the constants and D2D_2 replaces column 2 with the constants.

System: 2x1+3x2=52x_1+3x_2=5 and 11x1−5x2=611x_1-5x_2=6.

  1. Coefficient determinant: D=∣2311−5∣=2(−5)−3(11)=−10−33=−43≠0D=\begin{vmatrix}2&3\\11&-5\end{vmatrix}=2(-5)-3(11)=-10-33=-43\neq 0, so a unique solution exists.
  2. Replace column 1 with the constants: D1=∣536−5∣=5(−5)−3(6)=−25−18=−43D_1=\begin{vmatrix}5&3\\6&-5\end{vmatrix}=5(-5)-3(6)=-25-18=-43. …

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