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Q.The system of linear equations 2x+ky=72x + ky = 7 3x+2y=73x + 2y = 7 will be consistent, if : (A) k=43k = \dfrac{4}{3} (B) k≠43k \neq \dfrac{4}{3} (C) k≠34k \neq \dfrac{3}{4} (D) k=34k = \dfrac{3}{4}

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The system fails (parallel lines) only at k=43k=\tfrac{4}{3}; hence it is consistent for every k≠43k \neq \tfrac{4}{3}.

For a1x+b1y=c1a_1x+b_1y=c_1, a2x+b2y=c2a_2x+b_2y=c_2: a unique solution exists iff a1a2≠b1b2\dfrac{a_1}{a_2} \ne \dfrac{b_1}{b_2}; the system is inconsistent iff a1a2=b1b2≠c1c2\dfrac{a_1}{a_2}=\dfrac{b_1}{b_2}\ne\dfrac{c_1}{c_2}.

  1. Identify coefficients: a1=2, b1=k, c1=7a_1=2,\ b_1=k,\ c_1=7 and a2=3, b2=2, c2=7a_2=3,\ b_2=2,\ c_2=7.
  2. Unique solution (consistent) when 23≠k2\dfrac{2}{3} \ne \dfrac{k}{2}, i.e. k≠43k \ne \dfrac{4}{3}. …

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