Study the given pedigree chart and answer the questions that follow. (a) Is the trait given in the chart domin

Question

Q. Study the given pedigree chart and answer the questions that follow.

(a) Is the trait given in the chart dominant or recessive ? Give reason in support of your answer.

(b) Is this trait autosomal or sex-linked ? Give reason in support of your answer.

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Concept understanding — Mendelian Genetics Basics

Mendelian Genetics Basics

Imagine you have a box of coloured beads — red and white. If you pick one bead from the box, you get either red or white. Now imagine that the colour of your eyes, or the shape of your earlobe, is decided by something like that: a tiny "packet" inside your cells that comes in two versions, and you inherit one from each parent. That is the core idea of Mendelian genetics.

The everyday intuition

You have probably noticed that children often look like their parents — same hair colour, same dimples, same height. But they are never exact copies. Why? Because each parent contributes half of the "instructions" for building a child. Those instructions come in pairs, one from mother and one from father. Sometimes one instruction overrides the other; sometimes they blend. Gregor Mendel, a 19th-century monk, figured out the rules by watching pea plants — tall vs short, yellow vs green seeds — and counting what appeared in the next generation.

The precise meaning

Mendelian genetics is the study of how traits are passed from parents to offspring through genes. A gene is a unit of heredity — a stretch of DNA that codes for a specific characteristic, like flower colour. Each gene comes in different versions called alleles. For every gene, you inherit two alleles: one from your mother, one from your father.

If the two alleles are identical, you are homozygous for that trait. If they are different, you are heterozygous. In a heterozygous pair, one allele may be dominant — it shows up in the appearance — and the other recessive — it stays hidden unless both alleles are recessive.

Note

Mendel's key insight was that traits are not blended like paint. Instead, alleles remain separate and are passed on intact. A recessive allele can skip a generation and reappear later, unchanged.

Why it matters

Mendelian genetics is the foundation of modern biology. It explains:

Why some diseases run in families (like cystic fibrosis or sickle-cell anaemia)
How plant and animal breeders create new varieties
Why you might have your grandmother's eyes but not your mother's

The NCERT textbook states that Mendel's work established the laws of inheritance — the Law of Dominance, the Law of Segregation, and the Law of Independent Assortment. These laws describe how alleles separate during the formation of eggs and sperm, and how different genes are inherited independently of one another.

Key terms at a glance

Gene: a unit of heredity on a chromosome
Allele: a variant form of a gene
Dominant: the allele that expresses itself even when paired with a different allele
Recessive: the allele that expresses itself only when paired with an identical recessive allele
Homozygous: having two identical alleles for a gene
Heterozygous: having two different alleles for a gene …

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The trait is recessive because unaffected parents have an affected child. It is autosomal because an affected female has an unaffected father, ruling out X-linked recessive inheritance. The possible genotypes for children II-1 and II-3 are AA or Aa.

Understanding how to interpret pedigree charts is fundamental in genetics. The core idea is to look for specific patterns of inheritance that distinguish between dominant and recessive traits, and between autosomal and sex-linked traits. We use the presence or absence of the trait in parents and offspring, and its distribution across sexes, to deduce the mode of inheritance.

Analyze for Dominant vs. Recessive Inheritance (Part a)
- Concept:
  - A dominant trait typically appears in every generation, and affected individuals always have at least one affected parent. It does not "skip" generations.
  - A recessive trait can skip generations. A key indicator of a recessive trait is when two unaffected parents have an affected child. This is because the parents must both be carriers of the recessive allele without expressing the trait themselves.
- Application to the pedigree:
  - Observe individuals I-1 and I-2. Both are unaffected (represented by clear shapes).
  - They have an affected child, II-2 (represented by a shaded shape).
  - Since two unaffected parents have an affected offspring, the trait must be recessive. If it were dominant, at least one parent would have to be affected to pass on the dominant allele.
Watch out

A common mistake is to assume a trait is dominant just because it appears in multiple generations. Always look for the "unaffected parents, affected child" pattern to confirm recessiveness.
Analyze for Autosomal vs. Sex-linked Inheritance (Part b)
- Concept:
  - Autosomal traits affect males and females roughly equally and are inherited independently of sex chromosomes.
  - Sex-linked traits (most commonly X-linked) show different patterns in males and females due to the presence of only one X chromosome in males (XY) and two in females (XX).
    - For an X-linked recessive trait:
      - Affected females (XᵃXᵃ) must have an affected father (XᵃY) and at least a carrier mother (XᴬXᵃ or XᵃXᵃ).
      - Affected males (XᵃY) inherit the trait from their mother.
      - It is generally more common in males than females.
- Application to the pedigree:
  - We have already established that the trait is recessive. Now we need to determine if it's autosomal recessive or X-linked recessive.
  - Look at the affected female, II-2. For her to be affected by an X-linked recessive trait, her genotype would be XᵃXᵃ.
  - This means she must have inherited one Xᵃ allele from her mother (I-2) and one Xᵃ allele from her father (I-1).
  - If her father (I-1) contributed an Xᵃ allele, his genotype would be XᵃY, meaning he would be affected.
  - However, individual I-1 is shown as unaffected in the pedigree.
  - This contradiction rules out X-linked recessive inheritance. Therefore, the trait must be autosomal.
Determine Possible Genotypes (Part c)
- Concept: …

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Same / Similar Concept — real previous-year questions on the same or a closely similar concept, not this exact question.

Showing the 12 most recent of 62 on this concept.

CBSE 2026Set EG1 mark
$Q. Who proposed the chromosomal theory of inheritance?$
›Reveal solutionSolution

The chromosomal theory of inheritance was put forward by Sutton and Boveri (1902).

Working independently, Walter Sutton and Theodor Boveri noticed that the behaviour of chromosomes during meiosis exactly parallels the behaviour of Mendel's 'factors' (genes) — they occur in pairs, segregate during gamete formation and assort independently. Around 1902 they proposed the chromosomal theory of inheritance, stating that genes are located on chromosomes, and that the pairing and separation of chromosomes is the physical basis of …

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CBSE 2026Set A1 markMCQ
$Q. Which of the following laws is based on monohybrid cross?$
(a) Law of dominance
(b) Law of segregation
(c) Law of independent assortment
(d) Both (A) and (B)
›Reveal solutionSolution

A monohybrid cross reveals the Law of Dominance and the Law of Segregation; independent assortment needs a dihybrid cross.

Mendel's monohybrid cross (a single-character cross) showed that one allele masks the other in the F1 (Law of Dominance) and that the paired factors separate during gamete formation so each gamete carries only one, reappearing in the 3:1 F2 ratio (Law of Segregation). T …

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CBSE 2026Set BOTANY1 markMCQ
$Q. The genotypic ratio of F2 generation of Mendel's monohybrid cross is _____.$
(a) 3 : 1
(b) 1 : 2 : 1
(c) 2 : 2
(d) 1 : 1
›Reveal solutionSolution
In a monohybrid cross, the F2 phenotypic ratio is 3:1 but the underlying genotypic ratio is 1:2:1.

In Mendel's monohybrid cross (e.g. tall (TT) x dwarf (tt) pea plants), the F1 generation is entirely heterozygous (Tt) and phenotypically tall, since tallness is dominant. When F1 plants are self-pollinated, each parent contributes either a T or a t gamete with equal probability (1/2 each). Using a Punnett square, the F2 offspring genotypes appear in the ratio:

TT (homozygous dominant) : 1/4

Tt (heterozygous) : 1/2 (i.e. 2/4, from Tt and tT)

tt (homozygous recessive) : 1/4 …
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CBSE 2026Set ANNUAL1 markMCQ
$Q. Who rediscovered the results of Mendel's inheritance of characters?$
(a) Devries, Correns and Tschermak
(b) Sutton and Boveri
(c) Schleiden, Schwann and Morgan
(d) Watson and Crick
›Reveal solutionSolution

Mendel's 1865 findings were ignored for about 35 years until three botanists independently rediscovered the same laws of inheritance in 1900.

Mendel presented his laws of inheritance in 1865, but their significance was not understood at the time and the work was ignored for about 35 years. In 1900, Hugo de Vries, Carl Correns and Erich von Tschermak independently rediscovered Mendel's results while working on different plants, and gave due credit to Mendel's original work. Sutton and Boveri later proposed the chromosomal theory of inherit …

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CBSE 2026Set ANNUAL1 markMCQ
$Q. When the genotype of an organism contains two identical alleles, the organism is considered as$
(a) Homozygous
(b) Heterozygous
(c) Hemizygous
(d) Pleiotropy
›Reveal solutionSolution
Two identical alleles at a locus (e.g., TT or tt) make the organism homozygous; two different alleles (Tt) make it heterozygous.

In diploid organisms, each gene locus carries two alleles, one inherited from each parent.

If both alleles are identical (e.g., TT or tt), the genotype is homozygous (true-breeding) for that trait.

If the two alleles are different (e.g., Tt), the genotype is heterozygous.

Hemizygous refers to having only a single copy of a gene/allele (as with X-linked genes in a male, who has only one X chromosome). …
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CBSE 2026Set ANNUAL1 markMCQ
$Q. Crosses between F1 offspring and either of their parents are called as$
(a) Inbreeding
(b) Back cross
(c) Dihybrid cross
(d) Test cross
›Reveal solutionSolution
A back cross is any cross of an F1 hybrid with one of its own parents; a test cross is the specific back cross to the homozygous recessive parent used to determine genotype.

Back cross: F1 offspring crossed with either parent (dominant homozygous OR recessive homozygous) — used generally in breeding programmes to study inheritance or improve stock.

Test cross: a specific type of back cross — F1 (of unknown genotype for a trait) crossed specifically with the homozygous recessive parent, used to determine whether the F1 is homozygous or heterozygous for the dominant trait. …
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CBSE 2026Set ANNUAL1 mark
$Q. ............. A cross between an organism of an unknown genotype and homozygous recessive organism.$
›Reveal solutionSolution

A test cross is a cross between an individual of unknown genotype and a homozygous recessive individual, used to determine whether the unknown individual is homozygous dominant or heterozygous.

In a test cross, an organism showing a dominant phenotype (whose genotype could be either homozygous dominant, e.g. TT, or heterozygous, e.g. Tt) is crossed with a homozygous recessive organism (tt). If all offspring show the dominant phenotype, the unknown parent was hom …

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CBSE 2026Set ANNUAL1 markMCQ
$Q. A pure tall (TT) plant is crossed with a pure dwarf (tt) plant to produce F1 offspring. The F1 offspring are then self-crossed. What is the ratio of true-breeding tall (TT) to true-breeding dwarf (tt) plants in the F2 generation?$
(a) 1 : 1
(b) 1 : 2 : 1
(c) 1 : 3
(d) 3 : 1
›Reveal solutionSolution
The F2 of a monohybrid cross gives a 1 TT : 2 Tt : 1 tt genotypic ratio; the two true-breeding types (TT and tt) are therefore in a 1 : 1 ratio.

From the CBSE/NCERT Principles of Inheritance and Variation chapter (Mendel's monohybrid cross):

Parents: TT (tall) × tt (dwarf).

F1: all Tt (tall).

F1 selfed (Tt × Tt) gives the F2 Punnett square:

T t
T TT Tt
t Tt tt

Genotypic ratio = 1 TT : 2 Tt : 1 tt. …
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CBSE 2025Set 57/4/11 markMCQ
$Q. In a pea plant (Pisum sativum) inflated pod shape is dominant over constricted pod shape. The expected ratio of phenotypes of the offspring in a cross between both the parents with heterozygous inflated pod shape will be : (A) 1 : 0 (B) 1 : 1 (C) 2 : 1 (D) 3 : 1$
›Reveal solutionSolution
A cross between two heterozygotes (Ii × Ii) follows Mendel's monohybrid ratio: three offspring show the dominant phenotype (inflated) for every one showing the recessive (constricted). The answer is 3 : 1.

This is a classic Mendelian monohybrid cross. When both parents are heterozygous for a single trait, each carries one dominant and one recessive allele. The dominant allele masks the recessive in the phenotype, but the recessive can still be passed to offspring. The question tests whether you recognize the signature 3:1 phenotypic ratio that emerges when dominance is complete.

Let's denote the allele for inflated pod shape as I (dominant) and constricted pod shape as i (recessive). Both parents are heterozygous inflated, so their genotype is Ii.

Step-by-step analysis

Set up the cross

Parent 1: Ii (heterozygous inflated)

Parent 2: Ii (heterozygous inflated)

Determine the gametes

Each heterozygous parent produces two types of gametes in equal proportion: I and i.

Construct the Punnett square

Cross the gametes from both parents:

I (from Parent 2) i (from Parent 2)
I (from Parent 1) II Ii
i (from Parent 1) Ii ii

Identify the genotypes

The offspring genotypes are:

II : 1 (homozygous dominant) …
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CBSE 2025Set 57/4/11 markMCQ
$Q. Assertion (A) : ABO blood grouping in humans is an example of multiple allelism. Reason (R) : More than two genes in a population govern the same character in ABO blood grouping in humans.$
›Reveal solutionSolution
Multiple allelism means more than two alleles of a single gene exist in a population. ABO blood grouping is controlled by three alleles (I^A, I^B, i) of one gene, so Assertion is true. But the Reason says "more than two genes" — that is wrong; it's one gene with multiple alleles. Hence Assertion is true but Reason is false.

The core concept: What multiple allelism really means

When you hear "multiple alleles," the trap is to think it means "many genes." It does not. Multiple allelism refers to a single gene locus that has more than two possible allele variants present in the population. Any one diploid individual still carries only two alleles (one from each parent), but across the population, three or more different versions of that gene exist.

ABO blood grouping is the classic textbook example. The gene involved is the ABO gene on chromosome 9. It has three common alleles: I^A, I^B, and i. The I^A and I^B alleles are co-dominant (both expressed when together), and both are dominant over i. This gives the six possible genotypes and four blood group phenotypes you know.

Now look at the Reason statement carefully. It says: "More than two genes in a population govern the same character." That is a fundamental error. It is not "more than two genes" — it is more than two alleles of the same gene. The Reason misstates the definition of multiple allelism.

Step-by-step reasoning

Check the Assertion (A).

ABO blood grouping in humans is indeed an example of multiple allelism because three alleles (I^A, I^B, i) of a single gene exist in the human population. So Assertion is true.

Check the Reason (R). …
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CBSE 2025Set 57/5/11 markMCQ
$Q. During a monohybrid cross involving a tall pea plant with a dwarf pea plant, the offspring populations were tall and dwarf in equal ratio. Find out the genotype of parent pea plants. (A) Tt \times tt (B) TT \times Tt (C) tt \times tt (D) Tt \times Tt$
›Reveal solutionSolution
The parent pea plants must have genotypes Tt (heterozygous tall) and tt (homozygous dwarf) to produce tall and dwarf offspring in an equal 1:1 ratio.

To understand the genotypes of the parent pea plants, we first need to recall the fundamental principles of Mendelian genetics, specifically concerning a monohybrid cross. A monohybrid cross involves studying the inheritance of a single pair of contrasting characters, such as plant height in pea plants. Gregor Mendel's experiments established that certain traits are dominant and others are recessive.

In pea plants, tallness is a dominant trait, while dwarfness is a recessive trait. This means that if an allele for tallness (let's denote it as 'T') is present, the plant will be tall, even if it also carries an allele for dwarfness. The allele for dwarfness (let's denote it as 't') will only express itself if two copies of it are present in the plant's genetic makeup.

Note

An allele is an alternative form of a gene. For instance, the gene for plant height has two alleles: 'T' for tall and 't' for dwarf.

A plant's genotype refers to its genetic constitution (the combination of alleles it possesses), while its phenotype is the observable characteristic (what it looks like).

For the trait of height in pea plants, the possible genotypes and their corresponding phenotypes are:

TT: Homozygous dominant, Phenotype: Tall

Tt: Heterozygous, Phenotype: Tall (because 'T' is dominant over 't')

tt: Homozygous recessive, Phenotype: Dwarf

We are given a monohybrid cross between a tall pea plant and a dwarf pea plant. The offspring population shows tall and dwarf plants in an equal ratio, meaning 1 tall plant for every 1 dwarf plant, or a 1:1 ratio. Our task is to determine the genotypes of the parent plants that would produce this specific offspring ratio.

Let's consider the dwarf parent first. Since dwarfness is a recessive trait, a pea plant can only be dwarf if its genotype is homozygous recessive, meaning it must have two copies of the dwarf allele.

Therefore, the genotype of the dwarf parent is tt.

Now, let's consider the tall parent. A tall pea plant can have one of two possible genotypes: TT (homozygous tall) or Tt (heterozygous tall). We need to test which of these, when crossed with a tt dwarf plant, yields a 1:1 ratio of tall to dwarf offspring.

Scenario 1: Tall parent is homozygous dominant (TT)

If the tall parent is TT, the cross would be TT × tt.

The TT parent produces only 'T' gametes.

The tt parent produces only 't' gametes.

When these gametes combine, all offspring will have the genotype Tt.

Since Tt plants are tall, all offspring would be tall.

The phenotypic ratio would be 100% Tall, or 1 Tall : 0 Dwarf. …
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CBSE 2025Set ANNUAL1 markMCQ
$Q. Number of chromosomes found in human beings is-$
(a) Four Pairs
(b) Twenty two pairs
(c) Twenty three pairs
(d) Twenty four pairs
›Reveal solutionSolution

A normal human somatic cell contains 23 pairs (46) of chromosomes.

Every normal human somatic (diploid) cell contains 46 chromosomes arranged as 23 homologous pairs — 22 pairs of autosomes and 1 pair of sex chromosomes (XX in females, XY in males). Gametes (sperm and ova) are haploid and carry only 23 chromos …

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	I (from Parent 2)	i (from Parent 2)
I (from Parent 1)	II	Ii
i (from Parent 1)	Ii	ii

Q.Study the given pedigree chart and answer the questions that follow.

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