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Q.Hoffmann Bromamide degradation reaction is given by : (A) ArNO2ArNO_2 (B) ArNH2ArNH_2 (C) ArCONH2ArCONH_2 (D) ArCH2NH2ArCH_2NH_2

CBSECBSE Class XII Board 2025MCQ· 1mImportance★★★★★
✓ Free question

The Hoffmann bromamide degradation converts a primary amide (RCONHX2\ce{RCONH2}) into a primary amine with one fewer carbon atom using bromine and base. The starting material is ArCONHX2\ce{ArCONH2}, option (C).

The Hoffmann bromamide degradation is one of the most elegant reactions in organic chemistry for shortening a carbon chain while introducing an amino group. Understanding what it does—and what it requires—makes the answer obvious.

The Core Concept

The reaction takes a primary amide (RCONHX2\ce{RCONH2}) and, through treatment with bromine in aqueous or alcoholic alkali (typically NaOH\ce{NaOH} or KOH\ce{KOH}), removes the carbonyl carbon entirely. The product is a primary amine (RNHX2\ce{RNH2}) with one carbon atom less than the starting amide.

The key transformation:

RCONHX2→−COX2BrX2/NaOHRNHX2\ce{RCONH2 ->[Br2/NaOH][-CO2] RNH2}

The carbonyl carbon is lost as carbonate, and the nitrogen that was part of the amide becomes the amino group of the amine. This is why it's called a "degradation"—you're stepping down the carbon skeleton.

Why This Mechanism Matters

The reaction proceeds through several intermediates:

  1. N-bromoamide formation: Bromine in base first converts the amide to an N-bromoamide (RCONHBr\ce{RCONHBr}).

  2. Isocyanate intermediate: Base abstracts the remaining N–H proton, and the resulting anion loses bromide to form an isocyanate (R−N=C=O\ce{R-N=C=O}). This is the crucial rearrangement step—the alkyl/aryl group migrates from carbon to nitrogen.

  3. Hydrolysis: The isocyanate is rapidly hydrolyzed by the aqueous base to give a carbamic acid (RNHCOOH\ce{RNHCOOH}), which immediately decarboxylates to yield the primary amine (RNHX2\ce{RNH2}).

Important

The starting material must be a primary amide (RCONHX2\ce{RCONH2}). Secondary or tertiary amides do not undergo this reaction because the mechanism requires an N–H hydrogen for the rearrangement.

Analyzing the Options

Now let's see which option fits:

(A) ArNOX2\ce{ArNO2} — This is a nitro compound (nitrobenzene and derivatives). It has no amide group and cannot undergo Hoffmann degradation. Nitro groups are reduced to amines by other methods (catalytic hydrogenation, metal/acid reduction).

(B) ArNHX2\ce{ArNH2} — This is already a primary aromatic amine (aniline and derivatives). It's a product of reactions that introduce amino groups, not a substrate for Hoffmann degradation.

(C) ArCONHX2\ce{ArCONH2} — This is a primary aromatic amide (benzamide and derivatives). It has the exact structure required: a carbonyl attached to NHX2\ce{NH2}. Treatment with BrX2/NaOH\ce{Br2/NaOH} will give ArNHX2\ce{ArNH2} (an aromatic amine) plus COX2\ce{CO2}.

(D) ArCHX2NHX2\ce{ArCH2NH2} — This is a primary benzylamine. It already has the amino group attached to a CHX2\ce{CH2} carbon, not a carbonyl. No amide, no Hoffmann degradation.

Tip

A quick mnemonic: Hoffmann degradation takes you from amide to amine with one less carbon. If you see CONHX2\ce{CONH2}, think Hoffmann.

The reaction is particularly useful in aromatic chemistry because it provides a clean route from aromatic carboxylic acids (via their amides) to aromatic amines:

ArCOOH→ArCONHX2→BrX2/NaOHArNHX2\ce{ArCOOH -> ArCONH2 ->[Br2/NaOH] ArNH2}

✓Final answer

The correct option is **(

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