Q.Hoffmann Bromamide degradation reaction is given by : (A) ArNO2 (B) ArNH2 (C) ArCONH2 (D) ArCH2NH2
Concept understanding — Aromatic Synthesis Route
Aromatic Synthesis Route – First Principles
Imagine you are a chef who has been given a plain wooden board and told to carve a specific shape out of it. You can cut away wood, but you cannot add wood back. That is exactly the problem in aromatic synthesis: you start with a simple, cheap aromatic ring (like benzene) and you need to attach specific groups at specific positions. The ring itself is already there — you cannot rearrange its carbon skeleton. So the entire challenge is where to put the next group, and how to get it there.
The "route" is the sequence of reactions you choose. The order matters enormously because the groups already on the ring control where the next group will go. A wrong order can give you the wrong isomer, or force you into a dead end.
The Core Idea: The Ring Directs
Every substituent already on a benzene ring has a directing effect — it tells the next incoming group to go to certain positions. There are two families:
- Ortho/para directors (e.g., –OH, –NH₂, –CH₃, –Cl) — they push the next group to positions 2 and 4 (ortho and para).
- Meta directors (e.g., –NO₂, –CN, –CHO, –SO₃H) — they push the next group to position 3 (meta).
A common mistake is to think you can just "add any group in any order." The ring is not passive — it has a memory of what is already attached. If you ignore directing effects, you will get a mixture of products, often with the wrong isomer as the major one.
The Precise Statement
An aromatic synthesis route is a planned sequence of electrophilic aromatic substitution (EAS) reactions, chosen so that each new substituent is introduced at the correct position relative to the existing ones. The route must account for:
- Directing effects of all current substituents.
- Activation/deactivation — some groups make the ring more reactive (activators), some make it less reactive (deactivators). You cannot do a reaction on a strongly deactivated ring without special conditions.
- Order of introduction — sometimes you must introduce a meta director first, then an ortho/para director, or vice versa, to get the desired final pattern.
A Concrete Example: Making 4-Nitrobenzoic Acid
You want a benzene ring with –COOH at position 1 and –NO₂ at position 4 (para to each other).
–COOH is a meta director. –NO₂ is also a meta director. If you put –COOH first and then nitrate, the –COOH will send the –NO₂ to the meta position (3), not para (4). That gives the wrong isomer.
Correct route:
- Nitrate benzene first → nitrobenzene ( –NO₂ is meta directing).
- Then oxidise the methyl group (if you started with toluene) or use a different method to introduce –COOH. But wait — –NO₂ deactivates the ring strongly. So you cannot easily do Friedel-Crafts acylation on nitrobenzene.
So the actual correct route is different:
- Start with toluene (methylbenzene). The –CH₃ is an ortho/para director and an activator.
- Nitrate toluene → you get a mixture of ortho and para nitrotoluene. Separate the para isomer.
- Oxidise the –CH₃ to –COOH using KMnO₄. The –NO₂ survives this oxidation.
The order here is: introduce the ortho/para director first ( –CH₃ ), then nitrate to get para, then convert the –CH₃ to –COOH. If you had tried to put –COOH first, you would have a meta director that would send –NO₂ to the wrong place.
The General Strategy
When planning a route, ask yourself in order:
- What is the final substitution pattern? (1,2- ; 1,3- ; 1,4- ; etc.)
- Which groups are ortho/para directors and which are meta directors?
- Can I introduce the meta director first, then the ortho/para director? (Often yes, because meta directors deactivate the ring, making further substitution harder — so you want to do the deactivating step last if possible.)
- If I need a 1,3 pattern, I usually put a meta director first, then an ortho/para director. If I need a 1,4 pattern, I usually put an ortho/para director first, then a meta director (because the ortho/para director will send the next group to para, and the meta director will then be at the correct position).
The golden rule: The group that is introduced last must be compatible with the directing effect of the group already present. You cannot force a group to go where the ring does not want it to go.
One More Example: 1,3-Dinitrobenzene
You want two –NO₂ groups meta to each other.
–NO₂ is a meta director. So if you nitrate benzene once, you get nitrobenzene. Then nitrate again — the –NO₂ directs the second –NO₂ to the meta position. Perfect. The route is trivial: nitrate twice.
But if you wanted 1,4-dinitrobenzene, you cannot get it by direct nitration of benzene — the second –NO₂ will always go meta. You would need a different route (e.g., start with an ortho/para director, nitrate, then remove that director).
Summary
| Desired pattern | Typical strategy |
|---|---|
| 1,2- or 1,4- | Introduce an ortho/para director first, then the second group. |
| 1,3- | Introduce a meta director first, then the second group. |
| Three groups | Work stepwise, always checking the directing effect of the last group added. |
Final answer: An aromatic synthesis route is the deliberate ordering of electrophilic aromatic substitution reactions, chosen so that each new substituent is placed at the correct position by exploiting the directing effects of groups already on the ring. The order is not arbitrary — it is determined by whether the existing groups are ortho/para or meta directors, and by their activating or deactivating nature.
Planning a multi-step aromatic synthesis route using ortho/para- and meta-directing effects is a classic higher-order-thinking question style drawn from NCERT Class 11 and 12 Chemistry's organic chemistry chapters, and it shows up often in CBSE board "conversion and synthesis" questions as well as JEE Main. Students revising "directing effects in electrophilic substitution class 11 important questions" will find this step-by-step ordering logic directly useful.
Why this formula?
Aromatic Synthesis Route: Understanding the Why Behind the Key Principles
In organic chemistry, an aromatic synthesis route refers to a sequence of reactions designed to construct or modify an aromatic ring (typically benzene or its derivatives). The "key formulas" here are not single equations but rather rules and principles that govern reactivity and orientation. Let's break down the reasoning behind the most critical ones.
1. The 4n+2 Hückel Rule — Why Aromaticity Exists
Formula: A planar, cyclic, conjugated molecule is aromatic if it has (4n+2) π electrons, where n=0,1,2,…
Why this holds (the derivation):
- In a cyclic conjugated system, the π electrons occupy molecular orbitals (MOs) that form a ring.
- The energy levels of these MOs are given by the Frost circle (or polygon rule):
- For a regular polygon with N vertices (atoms), inscribe it in a circle with one vertex at the bottom.
- The energy of each MO corresponds to the vertical coordinate of each vertex.
- For benzene (N=6), the MOs split into:
- 1 low-energy bonding orbital
- 2 degenerate bonding orbitals
- 2 degenerate antibonding orbitals
- 1 high-energy antibonding orbital
- Key insight: The 6 π electrons fill the 3 bonding MOs completely. This gives a closed-shell, highly stable configuration — the aromatic stabilization energy (~150 kJ/mol for benzene).
- For N=4 (cyclobutadiene), the MO pattern gives 2 degenerate non-bonding orbitals — filling with 4 electrons creates an open-shell, antiaromatic (unstable) system.
Takeaway: The (4n+2) rule is not arbitrary — it emerges from the symmetry of cyclic π systems and the filling of bonding MOs.
2. Electrophilic Aromatic Substitution (EAS) — The Reactivity Formula
General reaction:
Ar-H+E+catalystAr-E+H+
Why this is the only viable route for aromatic rings:
- Aromatic rings are electron-rich (due to the π cloud) but resistant to addition — addition would break aromaticity.
- Mechanism reasoning:
- The electrophile E+ attacks the ring, forming a σ-complex (arenium ion) — this step is slow (rate-determining).
- The σ-complex is non-aromatic (4 π electrons in the ring) — it is high-energy and unstable.
- To regain aromaticity, the complex loses a proton (H+) — this step is fast and thermodynamically driven.
- Why substitution, not addition: Addition would permanently destroy aromaticity; substitution restores it.
Key formula: The rate law is Rate=k[Ar-H][E+] — first order in both, because the slow step involves both reactants.
3. Orientation Rules — Why Substituents Direct Where the Next Group Goes
Rule:
- Activating groups (e.g., −OH,−NH2,−OCH3) direct to ortho/para positions.
- Deactivating groups (e.g., −NO2,−CN,−CHO) direct to meta positions.
Why this happens (resonance + inductive reasoning):
For ortho/para directors:
- The substituent has a lone pair or π bond that can donate electrons into the ring via resonance.
- Draw the resonance structures of the σ-complex for attack at ortho, meta, and para:
- Ortho attack: The positive charge can be delocalized onto the substituent (e.g., −OH becomes =OH+). This stabilizes the intermediate.
- Para attack: Similar stabilization — charge delocalized to the substituent.
- Meta attack: The positive charge cannot reach the substituent — less stable.
- Result: Ortho/para intermediates are lower in energy → faster reaction.
For meta directors:
- The substituent is electron-withdrawing (by induction or resonance, e.g., −NO2).
- Draw resonance for ortho attack: The positive charge is placed directly on the carbon bearing the withdrawing group — this is highly destabilizing (like putting a + charge next to a + pole).
- For meta attack: The positive charge is never on the carbon with the withdrawing group — relatively more stable.
- Result: Meta attack is the least destabilized → preferred.
Key formula: The Hammett equation quantifies this:
log(k0k)=σρ
where σ is the substituent constant (electron-donating = negative, withdrawing = positive), and ρ is the reaction constant.
4. The Friedel-Crafts Acylation — Why It Works (and Alkylation Fails)
Reaction:
Ar-H+RCOClAlCl3Ar-COR+HCl
Why acylation is reliable but alkylation is messy:
- Acylation: The acylium ion R-C+=O is resonance-stabilized (the + charge is shared with oxygen). It is a moderately strong electrophile — reactive enough to attack the ring, but not so reactive that it causes polyalkylation.
- Alkylation: The carbocation R+ is highly reactive and can:
- Rearrange (e.g., 1° → 3°)
- Attack the product (which is more electron-rich than the starting material) → polyalkylation
- Key insight: The carbonyl group in the acyl product deactivates the ring (electron-withdrawing), so the reaction stops after one substitution.
Formula for success: Use acylation + Clemmensen/Wolff-Kishner reduction to get a clean alkylbenzene.
Summary Table: Why Each Principle Holds
| Principle | Core Reason |
|---|---|
| 4n+2 rule | Symmetry of cyclic MOs → closed-shell stability |
| EAS over addition | Aromaticity is too valuable to destroy |
| Ortho/para vs meta | Resonance stabilization of σ-complex |
| Acylation > alkylation | Acylium ion is stable; product is deactivated |
Final thought: Every aromatic synthesis route is a battle between reactivity and aromaticity. The "formulas" are not arbitrary — they are the mathematical and structural consequences of how electrons move in a ring. Master the why, and the what becomes obvious.
The Hoffmann bromamide degradation is a name reaction that converts a primary amide into a primary amine with one carbon less than the starting amide.
The reaction proceeds through treatment of an amide (RCONHX2) with bromine in aqueous or alcoholic alkali (NaOH/KOH). The mechanism involves formation of N-bromoamide, followed by rearrangement where the alkyl/aryl group migrates from carbonyl carbon to nitrogen, with loss of COX2.
For an aromatic amide ArCONHX2:
ArCONHX2BrX2/NaOHΔArNHX2+COX2
The aryl group shifts to nitrogen, yielding an aromatic primary amine (ArNHX2) as the product.
The Hoffmann bromamide degradation is given by (C) ArCONHX2 (aromatic primary amide).
The Hoffmann bromamide degradation converts a primary amide (RCONHX2) into a primary amine with one fewer carbon atom using bromine and base. The starting material is ArCONHX2, option (C).
The Hoffmann bromamide degradation is one of the most elegant reactions in organic chemistry for shortening a carbon chain while introducing an amino group. Understanding what it does—and what it requires—makes the answer obvious.
The Core Concept
The reaction takes a primary amide (RCONHX2) and, through treatment with bromine in aqueous or alcoholic alkali (typically NaOH or KOH), removes the carbonyl carbon entirely. The product is a primary amine (RNHX2) with one carbon atom less than the starting amide.
The key transformation:
RCONHX2BrX2/NaOH−COX2RNHX2
The carbonyl carbon is lost as carbonate, and the nitrogen that was part of the amide becomes the amino group of the amine. This is why it's called a "degradation"—you're stepping down the carbon skeleton.
Why This Mechanism Matters
The reaction proceeds through several intermediates:
-
N-bromoamide formation: Bromine in base first converts the amide to an N-bromoamide (RCONHBr).
-
Isocyanate intermediate: Base abstracts the remaining N–H proton, and the resulting anion loses bromide to form an isocyanate (R−N=C=O). This is the crucial rearrangement step—the alkyl/aryl group migrates from carbon to nitrogen.
-
Hydrolysis: The isocyanate is rapidly hydrolyzed by the aqueous base to give a carbamic acid (RNHCOOH), which immediately decarboxylates to yield the primary amine (RNHX2).
The starting material must be a primary amide (RCONHX2). Secondary or tertiary amides do not undergo this reaction because the mechanism requires an N–H hydrogen for the rearrangement.
Analyzing the Options
Now let's see which option fits:
(A) ArNOX2 — This is a nitro compound (nitrobenzene and derivatives). It has no amide group and cannot undergo Hoffmann degradation. Nitro groups are reduced to amines by other methods (catalytic hydrogenation, metal/acid reduction).
(B) ArNHX2 — This is already a primary aromatic amine (aniline and derivatives). It's a product of reactions that introduce amino groups, not a substrate for Hoffmann degradation.
(C) ArCONHX2 — This is a primary aromatic amide (benzamide and derivatives). It has the exact structure required: a carbonyl attached to NHX2. Treatment with BrX2/NaOH will give ArNHX2 (an aromatic amine) plus COX2.
(D) ArCHX2NHX2 — This is a primary benzylamine. It already has the amino group attached to a CHX2 carbon, not a carbonyl. No amide, no Hoffmann degradation.
A quick mnemonic: Hoffmann degradation takes you from amide to amine with one less carbon. If you see CONHX2, think Hoffmann.
The reaction is particularly useful in aromatic chemistry because it provides a clean route from aromatic carboxylic acids (via their amides) to aromatic amines:
ArCOOHArCONHX2BrX2/NaOHArNHX2
The correct option is **(
- CBSE 2025Set 56/4/11 markMCQQ.Hoffmann Bromamide degradation reaction is given by : (A) ArNO2 (B) ArNH2 (C) ArCONH2 (D) ArCH2NH2
›Reveal solutionSolution
The Hoffmann bromamide degradation converts a primary amide (RCONHX2) into a primary amine with one fewer carbon atom using bromine and base. The starting material is ArCONHX2, option (C).
The Hoffmann bromamide degradation is one of the most elegant reactions in organic chemistry for shortening a carbon chain while introducing an amino group. Understanding what it does—and what it requires—makes the answer obvious.
The Core Concept
The reaction takes a primary amide (RCONHX2) and, through treatment with bromine in aqueous or alcoholic alkali (typically NaOH or KOH), removes the carbonyl carbon entirely. The product is a primary amine (RNHX2) with one carbon atom less than the starting amide.
The key transformation:
RCONHX2BrX2/NaOH−COX2RNHX2
The carbonyl carbon is lost as carbonate, and the nitrogen that was part of the amide becomes the amino group of the amine. This is why it's called a "degradation"—you're stepping down the carbon skeleton.
Why This Mechanism Matters
The reaction proceeds through several intermediates:
-
N-bromoamide formation: Bromine in base first converts the amide to an N-bromoamide (RCONHBr).
-
Isocyanate intermediate: Base abstracts the remaining N–H proton, and the resulting anion loses bromide to form an isocyanate (R−N=C=O). This is the crucial rearrangement step—the alkyl/aryl group migrates from carbon to nitrogen.
-
Hydrolysis: The isocyanate is rapidly hydrolyzed by the aqueous base to give a carbamic acid (RNHCOOH), which immediately decarboxylates to yield the primary amine (RNHX2).
ImportantThe starting material must be a primary amide (RCONHX2). Secondary or tertiary amides do not undergo this reaction because the mechanism requires an N–H hydrogen for the rearrangement.
Analyzing the Options
Now let's see which option fits:
(A) ArNOX2 — This is a nitro compound (nitrobenzene and derivatives). It has no amide group and cannot undergo Hoffmann degradation. Nitro groups are reduced to amines by other methods (catalytic hydrogenation, metal/acid reduction).
(B) ArNHX2 — This is already a primary aromatic amine (aniline and derivatives). It's a product of reactions that introduce amino groups, not a substrate for Hoffmann degradation.
(C) ArCONHX2 — This is a primary aromatic amide (benzamide and derivatives). It has the exact structure required: a carbonyl attached to NHX2. Treatment with BrX2/NaOH will give ArNHX2 (an aromatic amine) plus COX2.
(D) ArCHX2NHX2 — This is a primary benzylamine. It already has the amino group attached to a CHX2 carbon, not a carbonyl. No amide, no Hoffmann degradation.
TipA quick mnemonic: Hoffmann degradation takes you from amide to amine with one less carbon. If you see CONHX2, think Hoffmann.
The reaction is particularly useful in aromatic chemistry because it provides a clean route from aromatic carboxylic acids (via their amides) to aromatic amines:
ArCOOHArCONHX2BrX2/NaOHArNHX2
✓Final answerThe correct option is **(
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- CBSE 2023Set 56/3/11 markMCQQ.Aspirin is obtained by the acetylation of which of the following compounds? (A) Salicylaldehyde (B) Salicylic acid (C) Acetyl salicylic acid (D) Phenol
›Reveal solutionSolution
Aspirin is synthesized by acetylating the hydroxyl group of salicylic acid with acetic anhydride or acetyl chloride, producing acetylsalicylic acid. The answer is (B).
Understanding Aspirin Synthesis
Aspirin, chemically known as acetylsalicylic acid, is one of the most widely used analgesic and anti-inflammatory drugs. The key to answering this question lies in understanding what acetylation means and recognizing the structural relationship between aspirin and its precursor.
Acetylation is the process of introducing an acetyl group (−COCHX3) into a molecule, typically by replacing an active hydrogen (usually on a hydroxyl or amino group) with −COCHX3.
When we say aspirin is "obtained by acetylation," we're looking for the compound that, when treated with an acetylating agent, gives us aspirin.
Step-by-Step Analysis
-
Identify aspirin's structure
Aspirin is acetylsalicylic acid, which has:
- A benzene ring
- A carboxylic acid group (−COOH) at position 1
- An acetyl ester group (−OCOCHX3) at position 2 (ortho to the carboxyl)
-
Work backwards from the product
If aspirin has an ester linkage (−OCOCHX3), then before acetylation, that position must have had a free hydroxyl group (−OH). The acetylation reaction converts −OH to −OCOCHX3.
-
Examine each option
(A) Salicylaldehyde has a benzene ring with −CHO (aldehyde) and −OH groups. Acetylating this would give an acetylated aldehyde derivative, not aspirin (which has a carboxylic acid group).
(B) Salicylic acid has:
- A carboxylic acid group (−COOH)
- A hydroxyl group (−OH) at the ortho position
When the −OH is acetylated, we get exactly aspirin's structure.
(C) Acetyl salicylic acid is aspirin itself. You can't obtain aspirin by acetylating aspirin.
(D) Phenol has only a hydroxyl group on benzene, no carboxylic acid. Acetylating phenol gives phenyl acetate, not aspirin.
-
The reaction
The industrial and laboratory synthesis of aspirin proceeds as:
CX6HX4(OH)(COOH)+(CHX3CO)X2OCX6HX4(OCOCHX3)(COOH)+CHX3COOH
Salicylic acid reacts with acetic anhydride (or acetyl chloride) in the presence of an acid catalyst (often sulfuric acid or phosphoric acid) to yield aspirin and acetic acid as a byproduct.
TipRemember the mnemonic: Salicylic acid + Acetylation = aSpirin. The "S-A-S" pattern helps recall that salicylic acid is the starting material.
Watch outDon't confuse the starting material with the product. Acetylsalicylic acid (option C) is the chemical name for aspirin itself, not what you start with. The question asks what compound is acetylated to obtain aspirin.
✓Final answerThe correct option is (B) Salicylic acid.
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