Q.Explain the Law of Equi-Marginal Utility.
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Start your 14-day free trial to unlock the full solution →A consumer attains maximum satisfaction when the ratio of marginal utility to price is equal for every good — the Law of Equi-Marginal Utility.
This 8-mark item is a central law of consumer behaviour in CHSE Odisha +2 Business Economics (the syllabus aligns with the NCERT/CBSE curriculum).
Meaning. A consumer has limited income but many wants. He will spend his income on various goods in such a way that the last rupee spent on each good yields him the same marginal utility. Only then is his total satisfaction greatest; if the satisfaction from a rupee differed across goods, he could gain by shifting spending from the lower-yielding to the higher-yielding good. Because the consumer keeps substituting, the law is also called the Law of Substitution or the Law of Maximum Satisfaction.
Statement. Other things being equal, a consumer is in equilibrium (gets maximum satisfaction) when the marginal utilities of the goods he buys are proportional to their prices — i.e. the marginal utility of money spent is equal in all uses:
- Marginal utility of X ÷ Price of X = Marginal utility of Y ÷ Price of Y = ... = Marginal utility of money.
Assumptions.
- Utility is measurable in cardinal units (utils).
- The consumer is rational and aims at maximum satisfaction.
- Income and prices of goods are given and constant.
- Marginal utility of money remains constant.
- The law of diminishing marginal utility operates.
Explanation with a numerical illustration. Suppose a consumer has 5 rupees to spend on two goods X and Y, each priced at Rs. 1. The marginal utility schedule (in utils) is:
| Unit (rupee) | MU of X | MU of Y |
|---|---|---|
| 1st | 20 | 16 |
| 2nd | 16 | 12 |
| 3rd | 12 | 10 |
| 4th | 8 | 8 |
| 5th | 6 | 6 |
To maximise satisfaction he picks the highest marginal utilities in turn: 20 (X), 16 (X), 16 (Y), 12 (X), 12 (Y) — spending 3 rupees on X and 2 on Y. At this allocation the marginal utility of the last rupee is equal (12 = 12), total utility (20+16+12 from X and 16+12 from Y = 76) is the maximum obtainable. Any other split (say 4 on X, 1 on Y) gives less total utility.
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