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Question Bank (2 marks) · Q2

Q.Draw DC load line and mark the end points.

Karnataka PUCTextbookShort· 2mImportance★★★★★est
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[!TLDR]

The load line is a straight line from IC(sat)=VCC/RCI_{C(sat)} = V_{CC}/R_C on the y-axis to VCE(cutoff)=VCCV_{CE(cutoff)} = V_{CC} on the x-axis.

From the collector-loop KVL equation VCC=VCE+ICRCV_{CC} = V_{CE} + I_C R_C, the two end points are found by setting each variable to zero:

  • y-axis (saturation) point, VCE=0V_{CE} = 0: IC(sat)=VCC/RCI_{C(sat)} = V_{CC}/R_C.
  • x-axis (cutoff) point, IC=0I_C = 0: VCE(cutoff)=VCCV_{CE(cutoff)} = V_{CC}.

On a graph of ICI_C (vertical axis) versus VCEV_{CE} (horizontal axis), mark IC(sat)I_{C(sat)} on the y-axis and VCE(cutoff)=VCCV_{CE(cutoff)} = V_{CC} on the x-axis, then join these two points with a straight line. This straight line is the DC load line, and its two marked ends are the saturation point and the cutoff point.

[!ANSWER]

The DC load line is the straight line joining the saturation point IC(sat)=VCC/RCI_{C(sat)} = V_{CC}/R_C (y-axis) and the cutoff point VCE(cutoff)=VCCV_{CE(cutoff)} = V_{CC} (x-axis).

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