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Worked Examples · Example 6

Q.Find the equation of the line passing through the points (1,2)(1, 2) and (3,8)(3, 8).

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The two-point form of the line through (x1,y1)(x_1, y_1) and (x2,y2)(x_2, y_2) is

y−y1=y2−y1x2−x1(x−x1)y - y_1 = \dfrac{y_2 - y_1}{x_2 - x_1}(x - x_1)

First compute the slope with (1,2)(1,2) and (3,8)(3,8):

m=8−23−1=62=3m = \dfrac{8 - 2}{3 - 1} = \dfrac{6}{2} = 3

Now apply the point-slope form using the point (1,2)(1, 2):

y−2=3(x−1) ⇒ y−2=3x−3 ⇒ y=3x−1y - 2 = 3(x - 1) \ \Rightarrow\ y - 2 = 3x - 3 \ \Rightarrow\ y = 3x - 1

In general form: 3x−y−1=03x - y - 1 = 0. …

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