Skip to content
Exercises · Q10

Q.A card is drawn from a pack of 5252. Are the events AA = "the card is a king" and BB = "the card is a heart" independent? Justify using probabilities.

Maharashtra MsbshseTextbookSubjectiveImportance★★★★★est
14% · 2/14 Questions
✓ Free question

There are 44 kings, 1313 hearts, and exactly one card that is both (the king of hearts). So

P(A)=452=113,P(B)=1352=14,P(A∩B)=152.P(A)=\frac{4}{52}=\frac{1}{13},\quad P(B)=\frac{13}{52}=\frac{1}{4},\quad P(A\cap B)=\frac{1}{52}.

Independence test. Compute the product:

P(A)⋅P(B)=113×14=152.P(A)\cdot P(B)=\frac{1}{13}\times\frac{1}{4}=\frac{1}{52}.

Since P(A∩B)=152=P(A) P(B)P(A\cap B)=\dfrac{1}{52}=P(A)\,P(B), the events satisfy the independence condition and are therefore independent.

Independent check via conditional probability. P(A∣B)=P(A∩B)P(B)=1/521/4=113=P(A)P(A\mid B)=\dfrac{P(A\cap B)}{P(B)}=\dfrac{1/52}{1/4}=\dfrac{1}{13}=P(A). Knowing the card is a heart does not change the probability it is a king, confirming independence.

✓Final answer

The events are independent, because P(A∩B)=152=P(A) P(B)P(A\cap B)=\dfrac{1}{52}=P(A)\,P(B) (equivalently P(A∣B)=P(A)=113P(A\mid B)=P(A)=\dfrac{1}{13}).

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.