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Worked Examples · Example 3

Q.Let U={1,2,3,…,10}U = \{1, 2, 3, \dots, 10\}, A={1,2,3,4,5}A = \{1, 2, 3, 4, 5\} and B={4,5,6,7}B = \{4, 5, 6, 7\}. Find

(i) A∪BA \cup B,
(ii) A∩BA \cap B,
(iii) A−BA - B,
(iv) A′A'.
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63% · 10/16 Questions
✓ Free question

Work from the definitions of each operation.

(i) Union A∪BA \cup B — all elements in AA or BB (or both), each listed once:

A∪B={1,2,3,4,5}∪{4,5,6,7}={1,2,3,4,5,6,7}.A \cup B = \{1, 2, 3, 4, 5\} \cup \{4, 5, 6, 7\} = \{1, 2, 3, 4, 5, 6, 7\}.

(ii) Intersection A∩BA \cap B — elements common to both:

A∩B={4,5}.A \cap B = \{4, 5\}.

(iii) Difference A−BA - B — elements in AA but not in BB; remove 44 and 55 (which are in BB) from AA:

A−B={1,2,3}.A - B = \{1, 2, 3\}.

(iv) Complement A′A' — elements of U={1,…,10}U = \{1, \dots, 10\} not in AA:

A′=U−A={6,7,8,9,10}.A' = U - A = \{6, 7, 8, 9, 10\}.

Cross-check using n(A∪B)=n(A)+n(B)−n(A∩B)n(A \cup B) = n(A) + n(B) - n(A \cap B): 5+4−2=75 + 4 - 2 = 7, and indeed A∪BA \cup B has 77 elements.

✓Final answer

(i) A∪B={1,2,3,4,5,6,7}A \cup B = \{1,2,3,4,5,6,7\} (ii) A∩B={4,5}A \cap B = \{4,5\} (iii) A−B={1,2,3}A - B = \{1,2,3\} (iv) A′={6,7,8,9,10}A' = \{6,7,8,9,10\}

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