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Worked Examples · Example 5

Q.For U={1,2,3,4,5,6,7,8}U = \{1,2,3,4,5,6,7,8\}, A={1,2,3,4}A = \{1,2,3,4\} and B={3,4,5,6}B = \{3,4,5,6\}, verify De Morgan's law (A∪B)′=A′∩B′(A \cup B)' = A' \cap B'.

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Left-hand side (A∪B)′(A \cup B)'.

A∪B={1,2,3,4}∪{3,4,5,6}={1,2,3,4,5,6}.A \cup B = \{1,2,3,4\} \cup \{3,4,5,6\} = \{1,2,3,4,5,6\}.

Its complement within U={1,…,8}U = \{1,\dots,8\} is

(A∪B)′=U−(A∪B)={7,8}.(A \cup B)' = U - (A \cup B) = \{7, 8\}.

Right-hand side A′∩B′A' \cap B'. First the individual complements:

A′=U−A={5,6,7,8},B′=U−B={1,2,7,8}.A' = U - A = \{5, 6, 7, 8\}, \qquad B' = U - B = \{1, 2, 7, 8\}.

Their intersection (elements in both):

A′∩B′={7,8}.A' \cap B' = \{7, 8\}.

Conclusion. Both sides equal {7,8}\{7, 8\}, so …

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