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Exercise 7.2 · Q33

Q.Find the equation of the ellipse in standard form if eccentricity = 3/8 and distance between its foci = 6.

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2ae=6⇒ae=32ae=6 \Rightarrow ae=3. With e=38e=\dfrac38: a=33/8=8⇒a2=64a=\dfrac{3}{3/8}=8 \Rightarrow a^2=64.

b2=a2(1−e2)=64(1−964)=64−9=55b^2=a^2(1-e^2)=64\left(1-\dfrac{9}{64}\right)=64-9=55. …

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