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Miscellaneous Exercise 3 (II) · Q89

Q.Prove the following: tan⁡20°tan⁡80°cot⁡50°=3\tan20°\tan80°\cot50°=\sqrt3

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✓ Free question

Step 1: cot⁡50°=tan⁡40°\cot50°=\tan40°, so the product is tan⁡20°tan⁡40°tan⁡80°\tan20°\tan40°\tan80°.

Step 2: Using tan⁡θtan⁡(60°−θ)tan⁡(60°+θ)=tan⁡3θ\tan\theta\tan(60°-\theta)\tan(60°+\theta)=\tan3\theta with θ=20°\theta=20°: the product equals tan⁡60°=3\tan60°=\sqrt3.

✓Final answer

tan⁡20°tan⁡80°cot⁡50°=3\tan20°\tan80°\cot50°=\sqrt3

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