Skip to content
Miscellaneous Exercise 3 (II) · Q114

Q.Prove the following: sin⁡π8=122−2\sin\dfrac{\pi}{8}=\dfrac{1}{2}\sqrt{2-\sqrt2}

Maharashtra MsbshseTextbookSubjectiveImportance★★★★★est
96% · 114/119 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Step 1: sin⁡2π8=1−cos⁡π42=1−222=2−24\sin^2\dfrac{\pi}{8}=\dfrac{1-\cos\frac{\pi}{4}}{2}=\dfrac{1-\frac{\sqrt2}{2}}{2}=\dfrac{2-\sqrt2}{4}. …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.