Skip to content
Miscellaneous Exercise 3 (II) · Q111

Q.Prove the following: sin⁡18°=5−14\sin18°=\dfrac{\sqrt5-1}{4}

Maharashtra MsbshseTextbookSubjectiveImportance★★★★★est
93% · 111/119 Questions
🔒 Locked · start free trial →

You're viewing a preview — the full solution, concept, methods & PYQ mapping are locked.

Start your 14-day free trial to unlock the full solution →

Step 1: Let θ=18°\theta=18°; then 2θ=36°,3θ=54°2\theta=36°,3\theta=54°, and 2θ+3θ=90°2\theta+3\theta=90°, so 2θ=90°−3θ2\theta=90°-3\theta, giving sin⁡2θ=sin⁡(90°−3θ)=cos⁡3θ\sin2\theta=\sin(90°-3\theta)=\cos3\theta.

Step 2: 2sin⁡θcos⁡θ=4cos⁡3θ−3cos⁡θ=cos⁡θ(4cos⁡2θ−3)2\sin\theta\cos\theta=4\cos^3\theta-3\cos\theta=\cos\theta(4\cos^2\theta-3); divide both sides by cos⁡θ≠0\cos\theta\ne0: 2sin⁡θ=4cos⁡2θ−3=4(1−sin⁡2θ)−3=1−4sin⁡2θ2\sin\theta=4\cos^2\theta-3=4(1-\sin^2\theta)-3=1-4\sin^2\theta.

Step 3: Rearrange into a quadratic in sin⁡θ\sin\theta: 4sin⁡2θ+2sin⁡θ−1=04\sin^2\theta+2\sin\theta-1=0. …

Unlock everything free for 14 days

  • Full step-by-step solutions
  • Concept-first explanations
  • Methods, shortcuts & mistakes
  • PYQ mapping + timed mock tests

Full access for 14 days. No credit card required.