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Q.Find out the EAN of [Zn(NH₃)₄]²⊕, [Fe(CN)₆]⁴⊖

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EAN = Z − (oxidation state) + 2 × (number of ligand donor pairs):

  • [Zn(NH₃)₄]²⁺: Z = 30, O.S. +2, 4 ligands → 30 − 2 + 8 = 36
  • [Fe(CN)₆]⁴⁻: Z = 26, O.S. +2, 6 ligands → 26 − 2 + 12 = 36 …

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